AMC 10 · 2006 · #15

Grade 8 geometry-2d
tangent-circlespythagorean-theoremsimilar-triangles area-difference ↑ Prerequisites: tangent-circlespythagorean-theorem
📏 Long solution 💡 4 insights 📊 Diagram
Problem
Two circles of radii 2 and 4 touch on the outside, and two lines are tangent to both. Find the area of the six-sided figure formed by the centres and the tangent points.

Pick an answer.

(A)
$18\sqrt {3}$
(B)
$24\sqrt {2}$
(C)
36
(D)
$24\sqrt {3}$
(E)
$32\sqrt {2}$
How to solve
Strategy Identify Subproblems

A concave hexagon looks scary, but Tool #7 (Identify Subproblems) turns it into pieces we already know. The line OP splits the figure into two mirror-image halves, and each half is just the quadrilateral OADP — a right trapezoid, because both radii OA and PD stand perpendicular to the same tangent line AD and are therefore parallel. So the plan is: (1) draw the radii to the tangent points and mark the right angles (Tool #1, Draw a Diagram); (2) build a right triangle to find the tangent length AD with the Pythagorean theorem; (3) find the area of the right trapezoid OADP; (4) double it, since symmetry (Tool #17) makes the lower half congruent to the upper half. Two known shapes replace one strange one.

1STEP 1

Draw the radii and spot the parallel sides

Radii to the same tangent are parallel, so a trapezoid appears.

OP=2+4=6, OA ⊥ AD, PD ⊥ AD → OA ∥ PD
2STEP 2

Build a right triangle to find AD

A right triangle inside gives the tangent length 4√(2).

PQ=4-2=2, AD=OQ=√(6²-2²)=√(32)=4√(2)
3STEP 3

Find the area of trapezoid OADP

The trapezoid's area is 12√(2).

[OADP]=1/2(OA+PD) · AD=1/2(2+4)(4√(2))=12√(2)
4STEP 4

Double it using the symmetry

Symmetry doubles it to 24√(2), choice (B).

[AOBCPD]=2·[OADP]=2 · 12√(2)=24√(2) → (B)
Answer
24√(2)
Turn the answer into a decimal to sanity-check: 24√(2)≈ 33.9. The tangent length came out to 4√(2)≈ 5.66, and one trapezoid to about 17, which looks right for a strip roughly 6 wide averaging 3 tall. The other choices sit noticeably apart — 18√(3)≈ 31.2, 36, 24√(3)≈ 41.6, 32√(2)≈ 45.3 — and only 24√(2) matches our computed value, so there is no rounding ambiguity. The √(2) is expected, since the tangent length √(32) produced it.
💡Key takeaway

A radius always meets its tangent at a right angle, so a tangent problem secretly hides right triangles and simple trapezoids — find them, and the Pythagorean theorem hands you the missing length.

  • Draw the radii and spot the parallel sides
  • Build a right triangle to find AD
  • Find the area of trapezoid OADP
  • Double it using the symmetry