AMC 10 · 2007 · #10
Grade 8 geometry-2dPick an answer.
The whole problem turns on one picture, so Tool #1 (Draw a Diagram) is primary: sketching the triangle inside the circle exposes the key fact that its longest side is a diameter. Getting there needs Tool #5 (Look for a Pattern) to recognize 3:4:5 as the famous Pythagorean triple, which makes the triangle a right triangle. Then Tool #4 (Introduce a Variable) sets a single scale factor k so the ratio sides 3,4,5 become real lengths, and Tool #7 (Identify Subproblems) splits the job into clean stages — prove it is right, find the diameter, scale the legs, then take the area.
Recognize the 3-4-5 right triangle
The ratio describes a right triangle.
Seeing 9+16=25 instantly flags the classic right-triangle triple hiding in the ratio.
8.G.B.6Look For A PatternThe hypotenuse is a diameter
So its longest side is a diameter.
The right angle points across to the widest span of the circle, which is a diameter.
The right angle points across to the widest span of the circle, so the hypotenuse is a diameter.
▸ Why?
Every point of the circle is one radius from the centre, so the longest chord is the one through the centre.
▸ Why?
An angle is right exactly when the squares on the two legs add up to the square on the third side.
Scale the ratio up to real lengths
That fixes the scale for all three sides.
One unknown stretch factor rescales the whole shape once you pin down a single real length.
7.G.A.1Introduce A VariableTake half of leg times leg
Half the product of the legs gives 8.64, choice (A).
Perpendicular legs already give you a base and a matching height, so no extra work is needed.
6.G.A.1Identify SubproblemsA 3-4-5 triangle is a right triangle, so its longest side stretches across the circle as the diameter; scale everything to match, then take half of leg times leg.
- Recognize the 3-4-5 right triangle
- The hypotenuse is a diameter
- Scale the ratio up to real lengths
- Take half of leg times leg