AMC 10 · 2008 · #1

Grade 4 counting
interval-arithmeticsequences-arithmetic systematic-enumeration ↑ Prerequisites: mental-arithmetic
📏 Medium solution 💡 1 insight
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Problem
A player scores exactly five baskets, each worth either two or three points. Count how many different totals are possible.

Pick an answer.

(A)
2
(B)
3
(C)
4
(D)
5
(E)
6
How to solve
Strategy Make a Systematic List

The phrase "how many different numbers" is the classic signal for Tool #2 (Make a Systematic List): with only 5 baskets there are just a few splits, so list them all instead of guessing. Tool #14 (Extreme Principle) pins the two ends of the list — all 2-pointers gives the smallest total, all 3-pointers the largest — and Tool #5 (Look for a Pattern) shows the totals climb by exactly 1 each step, so nothing in between is skipped or repeated.

1STEP 1

List the six possible splits

With the count fixed, only the split varies, giving six cases.

(3-pt, 2-pt) = (0,5),(1,4),(2,3),(3,2),(4,1),(5,0)
2STEP 2

Add up each split's total

Each swap raises the total by exactly one.

10, 11, 12, 13, 14, 15
3STEP 3

Check the extremes

The two extremes bracket everything from 10 to 15.

min=5·2=10, max=5·3=15
4STEP 4

Count the distinct totals

Nothing repeats, so the count is 6, choice (E).

10,11,12,13,14,15 → 6 values → (E)
Answer
6
The totals run from 10 to 15 with no gaps, and the count of whole numbers from 10 to 15 inclusive is 15-10+1=6, which agrees with the six listed totals. The answer 6 is exactly the number of baskets plus one, which makes sense: there are 6 choices for how many baskets are 3-pointers (0 through 5), and each choice gives a different total. Smaller choices like 5 come from forgetting one of the endpoint cases.
💡Key takeaway

When only one thing can change, list every case in order — here the totals climb from 10 to 15 by ones, so there are 6 of them.

  • List the six possible splits
  • Add up each split's total
  • Check the extremes
  • Count the distinct totals