AMC 10 · 2008 · #10

Grade 6 rate-ratio
ratefraction-arithmeticlinear-equations-one-var dimensional-analysisconvert-to-algebra ↑ Prerequisites: ratefraction-arithmetic
📏 Medium solution 💡 2 insights
Problem
Two workers with known solo times work together but at a joint rate lower than the sum of their rates. They still finish in a known time. Find the size of the job.

Pick an answer.

(A)
500
(B)
900
(C)
950
(D)
1000
(E)
1900
How to solve
Strategy Analyze the Units

Two different units are hiding in this problem, and noticing the clash is the whole game — so tool #8 (Analyze the Units) leads. The solo speeds are given as times to finish, which measures work in chimneys: 1/9 and 1/10 of a chimney per hour, numbers that stay the same no matter how big the chimney is. The chatter penalty is given in bricks: 10 bricks per hour, a flat count that also ignores the chimney's size. Those two scales only line up through the unknown N, and that single point of contact is what pins N down. Tool #16 (Change Focus) is how the contact gets made: instead of tracking the work they did, track the work they lost, because the loss is the one quantity that can be measured in both units. Tool #7 (Identify Subproblems) keeps the fraction bookkeeping in order, and tool #6 (Guess and Check) closes the argument by feeding the number back into the original story — showing N not only is forced, but actually works.

1STEP 1

Read each time as a rate

Each solo time becomes a rate.

Brenda: 1/9 chimney/hour. Brandon: 1/10 chimney/hour. Chatter: 10 bricks/hour.
2STEP 2

How much silence would have built

The sum of the rates would have built more than one job.

1/9+1/10=19/90, and 5·19/90=95/90=19/18
3STEP 3

The overshoot is exactly what talking cost

That overshoot is exactly what the slowdown cost.

19/18-1=1/18 of a chimney lost to talking
4STEP 4

Price the same loss in bricks

The same loss in absolute units is 50.

10 · 5=50 bricks lost, so 1/18 of a chimney =50 bricks
5STEP 5

Scale the piece to the whole

Scaling the piece to the whole gives 900.

1/18N=50 → N=18 · 50=900
6STEP 6

Check that 900 really works

Checking it forwards confirms 900, choice (E).

900/9+900/10-10=100+90-10=180, and 180 · 5=900
Answer
900
Three checks agree. First, timing: together the pair must beat both solo times, and 5 hours sits well under 9 and 10. If they never talked they would have finished in 90/19≈ 4.74 hours, so the small chatter tax should push the finish just past that — and 5 is just past it, not wildly past, which matches a penalty of only 10 bricks per hour against a 190-brick-per-hour pace. Second, whole numbers: 900 makes both solo speeds clean, 100 and 90 bricks per hour. Only a multiple of 90 can do that, and among 500, 900, 950, 1000, 1900 only 900 is a multiple of 90 — the others give ragged speeds like 1000/9≈ 111.1 bricks per hour. Third, scaling: the derivation says the chimney is always 90 times the hourly chatter loss, so a pair who lost 20 bricks per hour and still finished in 5 hours would be building an 1800-brick chimney. Chattier workers finishing in the same time means a smaller chimney is impossible and a bigger one is required, which is exactly the right direction.
💡Key takeaway

Measure the work they lost twice — once as a fraction of the chimney, once as a count of bricks — and setting those two measurements equal tells you how big the chimney is.

  • Read each time as a rate
  • How much silence would have built
  • The overshoot is exactly what talking cost
  • Price the same loss in bricks
  • Scale the piece to the whole
  • Check that 900 really works