AMC 10 · 2017 · #13

Grade 7 rate-ratio
rateratio-proportionunit-conversion dimensional-analysisidentify-subproblems ↑ Prerequisites: rateratio-proportion
📏 Medium solution 💡 3 insights
Problem
Part of a trip is driven slower and the total time is longer than usual. Find the distance.

Pick an answer.

(A)
132
(B)
135
(C)
138
(D)
141
(E)
144
How to solve
Strategy Analyze the Units

Everything here is distance, speed and time, and those three are locked together by distance = speed × time — so Tool #8 (Analyze the Units) is the engine. The useful consequence of that formula is this: over a fixed distance, speed and time move in opposite directions, so halving the speed doubles the time. That turns a pair of times into a ratio of speeds without ever solving an equation. First use Tool #7 (Identify Subproblems) to cut the trip into its two legs, since only the second leg is affected by the storm. Then use Tool #15 (Organize Information in More Ways) to lay the snowy day's timetable next to the usual day's timetable leg by leg — the comparison is where the ratio appears. The one number carrying real units, 20 miles per hour, is what converts that unit-free ratio into an actual speed. Tool #4 (Introduce a Variable) is held in reserve: naming the distance d and writing one equation also works, and it is used below as the cross-check.

1STEP 1

Split the trip at the storm

The first leg takes 60 minutes as usual.

t₁ = 1/3 × 180 = 60 minutes
2STEP 2

Time the snowy leg two ways

The second leg is timed two ways.

t₂ = 276 - 60 = 216 min t₂^usual = 2/3 × 180 = 120 min
3STEP 3

Turn the time ratio into a speed ratio

The time ratio flips into a speed ratio.

t₂/t₂^usual = 216/120 = 9/5 ⟹ v_snow = 5/9 v_usual
4STEP 4

Anchor the ratio with the 20 mph drop

The stated drop anchors the usual speed.

1 - 5/9 = 4/9, 4/9 v_usual = 20 ⟹ v_usual = 20 × 9/4 = 45 mph
5STEP 5

Convert speed and time to distance

Speed times time gives 135, choice (B).

180 min = 3 h, d = 45 mi/h × 3 h = 135 miles → (B)
Answer
135
Replay the snowy day with d = 135 miles. Usual speed is 135/3 = 45 miles per hour, matching the 180-minute normal trip. The first 1/3 is 45 miles at 45 miles per hour, which is 1 hour, or 60 minutes. The snowy speed is 45 - 20 = 25 miles per hour, and the remaining 90 miles at 25 miles per hour take 90/25 = 3.6 hours, or 216 minutes. Total: 60 + 216 = 276 minutes, exactly as stated. The sizes are also sensible: 25 miles per hour is a believable snowstorm crawl, and it should stretch a 120-minute stretch to 216 minutes, which it does. Testing the neighbouring choices separates them clearly — 132 miles gives 280 minutes and 138 miles gives about 272 minutes, so only 135 lands on 276.
💡Key takeaway

On the same stretch of road, whatever factor stretches the time shrinks the speed by that same factor — so 216 minutes instead of 120 means she drove at 5/9 speed, and the missing 4/9 being 20 miles per hour pins her usual speed at 45.

  • Split the trip at the storm
  • Time the snowy leg two ways
  • Turn the time ratio into a speed ratio
  • Anchor the ratio with the 20 mph drop
  • Convert speed and time to distance