AMC 10 · 2017 · #4

Grade 8 geometry-2d
pythagorean-theorempercentageratio-proportion convert-to-algebra ↑ Prerequisites: pythagorean-theorem
📏 Medium solution 💡 2 insights
Problem
One route follows two sides of a square and the other cuts across. Find the percent saved.

Pick an answer.

(A)
$30\%$
(B)
$40\%$
(C)
$50\%$
(D)
$60\%$
(E)
$70\%$
How to solve
Strategy Draw a Diagram

This is a paths-on-a-shape problem, so Tool #1 (Draw a Diagram) is the natural start: sketch the square and mark both routes. The two routes split into two independent measurements, so Tool #7 (Identify Subproblems) lets us find Jerry's total and Silvia's total separately. Jerry's total is two sides; Silvia's is the diagonal, which the right triangle inside the square turns into a Pythagorean length. Finally Tool #8 (Analyze the Units) keeps the comparison honest: 'how much shorter' means the gap measured as a percent of Jerry's trip.

1STEP 1

Draw it and measure Jerry's route

Setting the side to one makes both routes concrete.

J = 1 + 1 = 2
2STEP 2

Silvia's route is the diagonal

The straight route is a diagonal.

S = √(1² + 1²) = √(2)
3STEP 3

Find how much shorter the diagonal is

The gap is about 0.59.

J - S = 2 - √(2) ≈ 2 - 1.41 = 0.59
4STEP 4

Turn the gap into a percent

Dividing by the longer route gives 30 percent, choice (A).

(J - S)/J = 0.59/2 ≈ 0.29 = 29% → (A)
Answer
30%
The diagonal of a square is always shorter than going around two sides, so the answer must be a positive percent under 100%. The exact value is (2-√2)/2=1-√2/2≈ 0.293, which rounds to 29% — nearer to 30% than to 40%, confirming (A). Picking a different side length, say 10, gives Jerry 20 and Silvia √(200)≈ 14.14, again about 29% shorter, showing the scale did not matter.
💡Key takeaway

Cutting straight across a square instead of walking two sides saves you about 30% of the distance, because the diagonal is √2 times one side while two sides total 2.

  • Draw it and measure Jerry's route
  • Silvia's route is the diagonal
  • Find how much shorter the diagonal is
  • Turn the gap into a percent