AMC 10 · 2023 · #21

Grade 10 geometry-3d
cone-unrollingshortest-patharc-length-radiansimilar-figurespythagorean-theorem spatial-visualizationidentify-subproblemsshortest-path ↑ Prerequisites: pythagorean-theoremarc-length-radian
📏 Long solution 💡 5 insights
Problem
A lampshade is the slanted side surface of a cone with its tip cut off, open at both ends with no lids. Its height and the diameters of both openings are given. A bug sits on the bottom rim; honey sits on the top rim at the point farthest from the bug. The bug may only walk on the shade. Find the length of the shortest route.

Pick an answer.

(A)
$6 + 3\pi$
(B)
$6 + 6\pi$
(C)
$6\sqrt3$
(D)
$6\sqrt5$
(E)
$6\sqrt3 + \pi$
How to solve
Strategy Visualize Spatial Relationships

Shortest paths on a curved surface look hopeless until you notice what kind of curved surface this is. A cone is built entirely out of straight lines running from its tip to its rim, which means it can be slit and rolled flat without stretching anything (Visualize Spatial Relationships). Lengths along the surface survive that flattening untouched, so the curved question becomes a flat one, and on flat paper shortest means straight. Everything after that is bookkeeping about the flat picture (Draw a Diagram): where is the center, how far out are the two rims, how wide is the spread. The center is the cone's missing tip, so it has to be rebuilt from similar triangles with a named unknown (Introduce a Variable), and the two rim distances are slant heights, each its own small right-triangle computation (Identify Subproblems). Two traps sit in wait. The flattened spread is not a full turn — the rim keeps its length but lands on a bigger circle, so it wraps through a smaller angle. And the straight segment between the two points dives into the hole left by the top opening, so it is not a legal route (Eliminate Possibilities); the real shortest path is a string pulled taut around that hole (Extreme Principle), straight until it grazes the edge and then hugging it.

1STEP 1

Flatten the surface

Flattening preserves lengths.

lateral surface of a cone ⟶ flat region between two concentric arcs, all lengths preserved
2STEP 2

Rebuild the missing tip

Similarity rebuilds the tip.

3/6 = h/(h + 3√3) ⟹ 2h = h + 3√3 ⟹ h = 3√3, H = h + 3√3 = 6√3
3STEP 3

Slant heights become radii

The slant heights become the flat radii.

L = √((6√3)² + 6²) = √(108 + 36) = 12, ℓ = √((3√3)² + 3²) = √(27 + 9) = 6
4STEP 4

Identify the flat shape

The flat piece is a half-annulus.

θ = (rim length)/slant = (2π · 6)/12 = π radians = 180°
5STEP 5

Place the two points

Place the bug and the honey.

(6 - 3cosφ)² + (3sinφ)² + 27 = 72 - 36cosφ → φ = 180°; A = (12, 0), B = (6cos 90°, 6sin 90°) = (0, 6)
6STEP 6

The straight line leaves the shade

The straight line leaves the shade.

|AB| = √(12² + 6²) = 6√5, dist(O, AB) = 12/√5 ≈ 5.37 < 6
7STEP 7

Pull the string taut

Pull it taut against the inner rim.

∠ OCA = 90°, AC = √(OA² - OC²) = √(12² - 6²) = √(108) = 6√3
8STEP 8

Add the arc and finish

Adding the arc gives six root three plus pi.

cos(∠ AOC) = 6/12 = 1/2 → ∠ AOC = 60°, ∠ COB = 30° = π/6, arc CB = 6 · π/6 = π, AC + frown{CB} = 6√3 + π
Answer
6√3 + π
Numerically the answer is 6√3 + π ≈ 10.392 + 3.142 = 13.534, and it is boxed in tightly from both sides. Below: any route along the surface is at least the straight-line distance through the air between the two points, which is √(72 - 36cos 180°) = √(108) = 6√3 ≈ 10.392. That instantly kills choice (C), since equality would require the bug to tunnel straight through the lampshade. A sharper lower bound comes from the flat picture: any path from A to B in the plane is at least |AB| = 6√5 ≈ 13.416, so the answer must be strictly bigger than that — and 13.534 > 13.416, by less than one percent, which is just what you expect when the blocked line only dips about 0.63 inches into the hole. Above: an obviously legal but lazy route is to crawl halfway around the bottom rim and then straight up the slant, costing 12π/2 + 6 = 6π + 6 ≈ 24.85, which is choice (B). So (B) is a genuine path but plainly not the best one, and (A) at 6 + 3π ≈ 15.42 is also beaten by the 13.534 route already constructed. Only (E) lands in the narrow window just above 6√5. A direct numerical check confirms it: minimizing the length of the family "straight to the inner rim at angle φ, then wrap" over all feasible φ, and separately running a shortest-path search around the circular hole, both return 13.5338975, matching 6√3 + π to seven decimal places.
💡Key takeaway

A cone is a rolled-up sheet of paper, so unroll it and the shortest crawl turns into a straight line — except the shade's top opening leaves a hole in that sheet, so the line has to run straight until it grazes the hole and then hug the edge the rest of the way.

  • Flatten the surface into a plane
  • Rebuild the cone's missing tip
  • Slant heights become the two radii
  • The flat piece is a half-annulus
  • Place the bug and the honey
  • The straight line leaves the shade
  • Pull the string taut
  • Add the arc and finish