AMC 10 · 2017 · #4
Grade 7 rate-ratioPick an answer.
Tool #4 (Introduce a Variable): the bike half and the walk half cover the same unknown distance, so name that one distance d and both parts are described at once. Tool #8 (Analyze the Units): the speeds are kilometers per hour, so each time must be d ÷ speed in hours, which means the 44 minutes has to become a fraction of an hour first. Tool #7 (Identify Subproblems): split the 44 minutes into the bike time plus the walk time, write each as d over its speed, add them, and solve the single equation for d.
Name the equal half-distance
The key is that both legs are the same distance.
One letter covers both halves because they are the same length.
7.EE.B.4Introduce A VariableWrite each part's time
Each leg's time is that distance over its speed.
Dividing distance by speed always gives the time the trip lasts.
Dividing a distance by a speed always gives the time the trip lasts.
▸ Why?
At a steady pace the distance is the speed multiplied by the time, so dividing runs that backwards.
▸ Why?
The speed names a fixed distance per unit of time, so the time has to be counted in those same units.
Turn 44 minutes into hours
The given 44 minutes must become hours.
Match the time unit to the speed unit before adding anything.
6.RP.A.3Analyze The UnitsAdd the times and solve
Adding the times and solving gives the distance.
The two part-times stacked together must fill the whole 44 minutes.
5.NF.A.1Identify SubproblemsRound to the nearest tenth
Rounding gives 2.8.
Look at the next digit to decide whether the tenths digit stays or rises.
5.NBT.A.4Identify SubproblemsCall the equal half-distance d; biking takes d/17 hour and walking takes d/5 hour, and together they fill 44/60 hour, which gives d ≈ 2.8 kilometers — choice (C).
- Name the equal half-distance
- Write each part's time
- Turn 44 minutes into hours
- Add the times and solve
- Round to the nearest tenth