AMC 8 · 1999 · #7
Grade 4 arithmeticPick an answer.
AMC 8 1999 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The sentence asks one question but hides three short jobs, which is the signal for Tool #7 (Break into Subproblems): (i) find the total distance between the two exits, (ii) take of that distance, (iii) add the result to the starting milepost. Tool #1 (Draw a Diagram) backs this up — a simple number line from 40 to 160 makes "three-fourths of the way" visible as a tick mark, not just words, and prevents the common slip of computing of 160 instead of of the gap.
Subtract the two mileposts to find the gap between the exits: 120 miles.
Distance on a number line is the difference of the endpoints — a Grade 4 multi-step setup move.
4.OA.A.3Identify SubproblemsTake three-fourths of that gap — divide by 4, multiply by 3 — which is 90 miles.
Grade 4 fraction-of-a-whole: divide by the denominator, multiply by the numerator.
4.NF.B.4Identify SubproblemsStart at exit 3's milepost 40 and add the 90 miles to land at milepost 130 — choice (E).
Mileposts increase in the direction of travel, so adding distance to the starting milepost gives the new milepost.
4.OA.A.3Identify Subproblems"Fraction of the way from A to B" always means fraction of the gap B - A, then add back to A. Subtract, take the fraction, add — three Grade 4 moves and this AMC 8 problem is done.