AMC 8 · 2000 · #16
Grade 4 geometry-2darithmeticPick an answer.
AMC 8 2000 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Each English sentence in the problem turns directly into an equation, so Tool #13 (Convert to Algebra) is the natural fit: "25 lengths make 1000 m" becomes 25L = 1000, and "10 perimeters make 1000 m" becomes 10P = 1000. Tool #7 (Identify Subproblems) keeps the work orderly — solve for L first, then for P, then back out W from the perimeter formula, and finally compute the area. Each subproblem is a one-step Grade 4 division or substitution.
Translate each sentence into an equation: 25L = 1000 for the length, and 10P = 1000 for the perimeter P.
"n trips of distance d cover D" always means n · d = D — the Grade 4 multiplication-as-equal-groups idea.
4.OA.A.3Convert To AlgebraSolve for the length: divide 25L = 1000 by 25 to get L = 40 m.
25 × 40 = 1000 is a familiar fact — four quarters make a dollar, so forty quarters make ten dollars.
4.OA.A.3Identify SubproblemsSolve for the perimeter: divide 10P = 1000 by 10 to get P = 100 m.
Dividing by 10 shifts the digits one place — 1000 → 100.
4.OA.A.3Identify SubproblemsPut P = 100 and L = 40 into P = 2L + 2W and solve for the width: W = 10 m.
Once two sides (L = 40) of the four-sided trip are accounted for, the other two sides must add to 100 - 80 = 20, so each is 10.
4.MD.A.3Convert To AlgebraMultiply length by width: A = 40 × 10 = 400 m², choice (C).
Area of a rectangle is just length times width — the final Grade 4 step.
4.MD.A.3Identify SubproblemsEach sentence in a word problem can become one short equation. Solve them in order — length, then perimeter, then width, then area — and the answer is 40 × 10 = 400 m², choice (C).