AMC 8 · 2001 · #5
Grade 6 rate-ratioarithmeticPick an answer.
AMC 8 2001 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The numbers come dressed in three different units — seconds, feet per second, feet per mile — but the answer must be in miles. Tool #8 (Analyze the Units) gives the recipe: multiply feet/second by seconds to cancel "second" and land on feet, then divide by feet/mile to cancel "feet" and land on miles. Tool #7 (Identify Subproblems) splits that recipe into three clean steps — (a) feet of sound travel, (b) feet → miles, (c) round to the nearest half-mile — so each line does one job.
Multiply speed by time — feet/second × seconds cancels "second" and leaves feet: 1088 × 10 = 10,880 ft.
Rate × time is the Grade 6 rate-reasoning move; multiplying by 10 just shifts the digits one place.
6.RP.A.3Analyze The UnitsDivide feet by 5280 feet/mile — "feet" cancels and leaves miles: 10,880 ÷ 5280 ≈ 2.06 mi.
Converting feet to miles by the given factor 5280 is the Grade 5 "convert measurement units" standard.
5.MD.A.1Identify SubproblemsNearby half-mile marks are 2 and 2 ; 2.06 sits only 0.06 from 2, so round to 2 miles → (C).
Rounding to the nearest half is the same idea as Grade 5 decimal rounding — pick whichever benchmark is closer.
5.NBT.A.4Identify SubproblemsLet the units guide you: seconds times feet-per-second gives feet, then dividing by feet-per-mile gives miles. Sound covers 10,880 ft in 10 s, which is about 2.06 mi — closest to 2 miles, answer (C).