AMC 8 · 2002 · #13
Grade 6 geometry-3dPick an answer.
AMC 8 2002 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
We are not told Bert's actual dimensions, only that the count is 125. Tool #9 (Easier Related Problem) lets us pick convenient dimensions that match: a 5 × 5 × 5 cube of jellybeans gives exactly 125. Once the easy case is concrete, Carrie's box becomes 10 × 10 × 10 and we can multiply directly. Tool #7 (Identify Subproblems) handles the three independent doublings — length doubles, width doubles, height doubles — so the volume factor is 2 × 2 × 2 = 8, which explains why 125 × 8 = 1000 no matter what shape Bert's box really is.
Pick easy dimensions: since 125 = 5 × 5 × 5, model Bert's box as a 5 × 5 × 5 cube.
Grade 5 volume work: a rectangular prism's volume equals length × width × height, so any triple whose product is 125 will do — a cube is the simplest.
5.MD.C.5Solve An Easier Related ProblemDouble each side: Bert's 5 × 5 × 5 becomes a 10 × 10 × 10 box.
Each dimension is its own subproblem: length, width, and height all double independently.
5.MD.C.5Identify SubproblemsMultiply out Carrie's box: 10 × 10 × 10 gives 1000 jellybeans.
Same volume formula, bigger numbers — the answer matches choice (E).
5.MD.C.5Solve An Easier Related ProblemCheck with scaling: doubling three sides multiplies volume by 2 × 2 × 2 = 8, so Carrie holds 8 times Bert's count.
Grade 6 ratio reasoning: scaling each side by 2 scales the volume by the cube of 2. Any box, not just a cube, gets multiplied by 8.
6.RP.A.3Identify SubproblemsDoubling one side doubles the volume, doubling two sides quadruples it, doubling all three sides multiplies it by 8. That is why Carrie's box holds 125 × 8 = 1000 jellybeans.