AMC 8 · 2004 · #3
Grade 6 arithmeticPick an answer.
AMC 8 2004 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The portion size is the same in every meal, so meals and people form a fixed ratio: 12 meals match 18 people. That is the standard setup for Tool #3 (Set Up an Equation) — a proportion that says "meals over people stays constant." Tool #4 (Introduce a Variable) names the unknown number of meals x so we can solve. The cleanest path is to find the per-person rate (meals per person) first, then multiply by 12.
Let x be the number of meals that would feed exactly 12 people.
Giving the unknown a letter is the Grade 6 "write expressions with variables" move.
6.EE.A.2Use Matrix LogicSince 12 meals feed 18 people, each person eats 12 ÷ 18 = of a meal.
Dividing the two quantities turns a 12-to-18 ratio into the per-person share that every diner gets.
6.RP.A.2Eliminate PossibilitiesEach person needs of a meal, so x = 12 × = 8 meals.
Once you know the per-person share, scaling to any number of people is one multiplication.
6.RP.A.3Eliminate PossibilitiesSo 8 meals matches choice (A).
The per-person rate method lands exactly on a listed choice when the problem is well posed.
6.RP.A.3Eliminate PossibilitiesSharing problems become easy once you pin down the per-person share — find it once, then multiply by however many people you have.