AMC 8 · 2004 · #6
Grade 6 arithmeticPick an answer.
AMC 8 2004 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The problem links two percentages of the same shooter, so the natural move is Tool #3 (Set Up an Equation): write the new success rate as a fraction whose numerator and denominator both depend on what happens in the last 5 shots. Tool #4 (Introduce a Variable) names the unknown count x of made shots among those last 5, so we can turn the percentage sentence into a single linear equation and solve. Once x is isolated, the answer is one subtraction away.
Taking 55% of the first 20 shots gives Sally's makes so far: 11.
Percent of a whole is the Grade 6 "percent times total" move: 55% of 20 is 11.
6.RP.A.3Eliminate PossibilitiesLet x be the last-5 makes, so the total is 11 + x out of 25 shots.
One letter for the unknown count keeps the rest of the work as plain arithmetic.
6.EE.A.2Use Matrix LogicThe 56% rate is makes over total, so .
A percent equation is just a fraction set equal to a decimal — exactly what Grade 6 "solve px = q" handles.
6.EE.B.7Eliminate PossibilitiesMultiply by 25 to get 11 + x = 14, so x lands on choice (C).
Clearing the denominator turns the percent equation into one-step arithmetic.
6.EE.B.7Eliminate PossibilitiesPercent problems get easy once you turn the percent into a fraction with the right top and bottom. Here, 56% of 25 shots is exactly 14 makes, and Sally already had 11 — so she needed 14 - 11 = 3 more makes in those last 5 shots.