AMC 8 · 2005 · #22
Grade 7 rate-ratioPick an answer.
AMC 8 2005 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question asks only for a ranking, so the actual prices and sizes do not matter — only their ratios do. Tool #9 (Try a Simpler Case) lets us pick convenient round numbers for the small box without loss of generality, then derive the other two boxes from the percentage rules. Tool #4 (Introduce a Variable) backs this up: if you set the small box at cost c and size s, every other quantity is a fixed multiple of c or s, so the ratios cost/size only depend on those multiples. Picking c = $1 and s = 5 oz keeps the arithmetic clean.
Give the small box easy round numbers — cost $1, size 5 oz; any baseline gives the same ranking.
Grade 6 ratio reasoning: rankings depend on ratios, so any convenient baseline works.
6.RP.A.3Solve An Easier Related ProblemThe large holds twice the small, so size(L) = 10 oz; its cost is set later via the medium.
"Twice as much" is the cleanest ratio relation — apply it directly.
7.RP.A.3Use Matrix LogicMedium: cost is 50% more (· 1.5 = $1.50), size is 20% less than large (· 0.8 = 8 oz).
Grade 7 percent reasoning: "50% more" means multiply by 1.5; "20% less" means multiply by 0.8.
7.RP.A.3Use Matrix LogicLarge costs 30% more than medium: 1.3 · 1.95.
Same percent move: "30% more" scales by 1.3.
7.RP.A.3Use Matrix LogicUnit price = cost per oz: S = 0.1875, L = $0.195 — lower is better.
Grade 6 unit rate: divide cost by size to compare apples to apples.
6.RP.A.2Identify SubproblemsOrder the unit prices low to high: M < L < S, so the best-to-worst buy is (E).
The cheapest cost-per-ounce is the "best buy" — order from smallest to largest.
6.RP.A.3Identify SubproblemsWhen the question is "which is the best buy?", only cost per ounce matters — pick easy numbers for the small box, follow the percentages to the medium and large, then divide.