AMC 8 · 2006 · #18
Grade 6 geometry-3dPick an answer.
AMC 8 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Counting white unit-squares directly is messy — the edge and center cubes contribute different numbers of faces. Tool #16 (Count the Complement) flips the problem: count the black unit-squares instead. Black cubes sit only at the 8 corners, and Tool #17 (Visualize Spatially) tells us each corner cube shows exactly 3 faces on the surface. That makes the black count a single multiplication. Tool #7 (Identify Subproblems) keeps the work organized: (a) find the total surface, (b) find the black surface, (c) subtract, (d) form the fraction.
The big cube has 6 faces, each a 3×3 grid of 9 squares, giving 54 surface squares in all.
Grade 6 surface area: a cube's surface is 6 congruent square faces, and each face's area in unit squares is side² = 9.
6.G.A.4Identify SubproblemsThe 8 black cubes sit at corners, and each corner shows exactly 3 faces, so there are 24 black squares.
Visualize one corner: pick up a cube, look at the corner — three faces meet there. Grade 3 multiplication does the rest: 8 corners, 3 faces each.
3.OA.A.1Visualize Spatial RelationshipsEvery surface square is black or white, so subtract: 54 minus 24 leaves 30 white squares.
Counting the complement avoids tracking edge cubes and center cubes separately — black is small and easy, so subtract.
3.OA.A.1Count The ComplementWrite the white fraction and divide top and bottom by 6 to get .
Grade 4 equivalent fractions: 30 = 6 × 5 and 54 = 6 × 9, so = .
4.NF.A.1Count The ComplementWhen most of the surface is one color, count the other color instead — each of the 8 black corner cubes shows just 3 faces, so 24 black squares out of 54 leaves white.