AMC 8 · 2007 · #20
Grade 6 algebraPick an answer.
AMC 8 2007 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The problem already hands us five candidate totals, so Tool #6 (Guess and Check) is the most direct route — far simpler than setting up algebra. For each choice we know the games-before count (choice - 8), and we just check whether 45% of that is a whole number AND whether adding 6 wins puts us at exactly half the season total. Tool #3 (Eliminate Possibilities) sharpens the check: 45% = , so the games-before count must be a multiple of 20, which knocks out almost every choice instantly.
Let T be the season total: games before district play = T - 8, wins before = 45% of that, and half of T = (wins before) + 6.
Write everything in terms of the season total T so each guess becomes a single arithmetic check.
6.RP.A.3Guess And CheckSince 45% = , wins-before is whole only when T - 8 is a multiple of 20. Among the choices, only T - 8 = 40 qualifies.
Win counts must be whole numbers, and 45% forces a multiple of 20 — most choices fail this test before any deeper check.
6.RP.A.3Eliminate PossibilitiesCheck T = 48: games before = 40, wins before = 0.45 × 40 = 18, so 18 + 6 = 24 out of 48 — exactly 50%.
Wins go from 18 out of 40 to 24 out of 48 — a clean 45% → 50% jump powered by 6 extra wins in 8 extra games.
6.RP.A.3Guess And CheckThe rest fail the whole-number test: 0.45 × 42, 44, 46, 52 give 18.9, 19.8, 20.7, 23.4 — none whole. Only (A) survives.
Wins are countable objects; a fractional win count means the choice can't match a real season record. Answer: (A) 48.
6.RP.A.3Eliminate PossibilitiesSince 45% = , the games-before count has to be a multiple of 20 — that one fact narrows five answer choices to one. The Unicorns played 48 games in all.