AMC 8 · 2009 · #2

Grade 6 rate-ratio
ratio-proportionmulti-digit-arithmetic ratio-proportionpattern-recognition ↑ Prerequisites: multi-digit-arithmetic
📏 Short solution 💡 2 insights
Problem
At a dealership, for every 4 sports cars sold, 7 sedans are sold. Next month they expect to sell 28 sports cars. How many sedans should they expect to sell at the same rate?

Pick an answer.

(A)
7
(B)
32
(C)
35
(D)
49
(E)
112

AMC 8 2009 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Look for a Pattern

The phrase "for every 4 sports cars, 7 sedans" sets up a repeating pattern: (4, 7), (8, 14), (12, 21), … — each step adds one more 4 : 7 group. Tool #5 (Look for a Pattern) makes that ladder visible and shows that the sports-car column is multiplied by some whole number to reach 28, so the sedan column gets multiplied by the same number. Tool #6 (Guess and Check) is the natural backup: test each answer choice against the 4 : 7 ratio and keep the one that matches.

1STEP 1

List the ratio as a table — each row is one 4 : 7 group, and each new group adds 4 sports cars and 7 sedans.

sports & sedans ; 4 & 7 ; 8 & 14 ; 12 & 21 ; vdots & vdots
2STEP 2

Find the scaling factor: 28 ÷ 4 = 7, so 28 sports cars is 7 groups of 4 : 7.

28 ÷ 4 = 7 groups
3STEP 3

Scale the sedan side the same way: 7 groups × 7 sedans each = 49 → (D).

sedans = 7 × 7 = 49 → (D)
Answer
49
Check the ratio: 28 : 49. Divide both by their common factor 7 to get 4 : 7 — exactly the original ratio. Also, sedans should outnumber sports cars (since 7 > 4), and 49 > 28 confirms the direction. Choices smaller than 28 (A: 7) or only slightly above (B: 32, C: 35) would not preserve the 4 : 7 shape, and (E) 112 is the sports-car count times 4, which is too aggressive.
💡Key takeaway

When two quantities grow at a constant ratio, find how many times one side is scaled up — then scale the other side by the same number.