AMC 8 · 2011 · #9

Grade 6 rate-ratio
rategraph-reading dimensional-analysis ↑ Prerequisites: rate
📏 Short solution 💡 2 insights 📊 Diagram
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Problem
Carmen rides her bike on a hilly highway. A graph plots her cumulative distance (in miles) against time (in hours). The graph starts at (0, 0) and ends at (7, 35), with bends at (1, 5), (2, 15), and (4, 20). What is her average speed for the entire ride in miles per hour?

Pick an answer.

(A)
2
(B)
2.5
(C)
4
(D)
4.5
(E)
5

AMC 8 2011 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Analyze the Units

The question asks for a rate in miles per hour, which screams Tool #8 (Analyze the Units): mph = miles/hours, so we just need one number for total miles and one number for total hours. Tool #3 (Draw a Picture) is already done for us — the graph is the picture — but we have to read it correctly: only the final point (7, 35) matters for the average, because everything in between is just "how she got there". The intermediate bends are a distractor that tempts students to average the segment speeds, which is wrong.

1STEP 1

The graph's rightmost point sits at x = 7 on the hours axis, so the whole ride lasted 7 hours.

total time = 7 hours
2STEP 2

The same endpoint sits at y = 35 on the miles axis, so Carmen rode a total of 35 miles.

total distance = 35 miles
3STEP 3

Average speed is total distance over total time; the units already match, so 35 miles over 7 hours gives 5 mph.

average speed = (35 mi)/(7 hr) = 5 mph → (E)
Answer
5
A casual bike ride on a hilly highway at about 5 mph is reasonable — closer to a brisk walk than a sport ride, which fits "hilly" terrain. Checking the segments: 0 → 5 mi in 1 hr (5 mph), 5 → 15 mi in 1 hr (10 mph downhill), 15 → 20 mi in 2 hr (2.5 mph uphill), 20 → 35 mi in 3 hr (5 mph). The total 5 + 10 + 5 + 15 = 35 mi over 1 + 1 + 2 + 3 = 7 hr confirms 35 / 7 = 5 mph.
💡Key takeaway

Average speed always means total distance ÷ total time — not the average of the speeds along the way!