AMC 8 · 2012 · #1

Grade 6 arithmetic
ratio-proportionratemulti-digit-arithmetic easier-related-problemdimensional-analysis ↑ Prerequisites: multi-digit-arithmeticfraction-arithmetic
📏 Short solution 💡 2 insights
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Problem
Rachelle uses 3 pounds of meat for 8 hamburgers. At the same rate, how many pounds of meat does she need for 24 hamburgers?

Pick an answer.

(A)
6
(B)
$6\dfrac{2}{3}$
(C)
$7\dfrac{1}{2}$
(D)
8
(E)
9

AMC 8 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Solve an Easier Related Problem

The numbers 8 and 24 are friendly: 24 is exactly 3 batches of 8. Tool #9 (Easier Related Problem) says — instead of fighting a proportion, recognize the smaller version we already solved (3 lb feeds 8 burgers) and copy it three times. Tool #8 (Analyze the Units) keeps the bookkeeping honest: the rate is "pounds per hamburger", so multiplying that rate by a number of hamburgers gives pounds — exactly what the question asks for.

1STEP 1

The big batch of 24 is exactly 3 of the small 8-burger batches (24 ÷ 8).

24 ÷ 8 = 3
2STEP 2

Same recipe, so the meat scales by that same factor of 3, giving 9 pounds.

meat = 3 × 3 lb = 9 lb
3STEP 3

The rate 38\frac{3}{8} lb per burger times 24 burgers cancels 'burgers' and leaves 9 pounds.

(3 lb)/(8 burgers) × 24 burgers = 3×248\frac{3 × 24}{8} lb = 728\frac{72}{8} lb = 9 lb → (E)
Answer
9
Common sense: 3 family-sized batches at 3 pounds each is 9 pounds total — that matches. The answer is bigger than 3 lb (we need more burgers, so we need more meat) and a whole number (because 24 is a whole multiple of 8). Answer choices like 6 23\frac{2}{3} or 7 12\frac{1}{2} would only appear if 24 weren't divisible by 8, so they can be ruled out by structure alone.
💡Key takeaway

When the new batch is just a whole-number multiple of the old batch, you don't need fancy proportions — multiply both sides by the same factor.