AMC 8 · 2012 · #19
Grade 6 algebraPick an answer.
AMC 8 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Each clue is phrased as a complement: "all but 6 are red" tells us T - r = 6, not r directly. Tool #16 (Count the Complement) is exactly that move — read "all but k" as the size of the non-that-color set. Tool #13 (Convert to Algebra) then lets us name T, r, g, b and add the three complement equations. The three left sides add to 3T - (r+g+b) = 3T - T = 2T, and the right sides add to 6 + 8 + 4 = 18, so T falls out in one line.
Read each clue as a complement: "all but 6 are red" means 6 marbles are not red, so T - r = 6; likewise T - g = 8 and T - b = 4.
"All but k are X" is a complement statement: it counts everything that is NOT X.
6.EE.A.2Count The ComplementAdd the three complement equations. The left side collapses to 3T - (r + g + b) and the right side to 6 + 8 + 4 = 18.
Adding three clean equations packages all three clues into one statement about T.
4.OA.A.3Convert To AlgebraSince r + g + b = T, the left side becomes 3T - T = 2T, so 2T = 18 and T = 9.
Replacing r + g + b with T collapses three unknowns into one, and a one-step linear equation finishes the job.
6.EE.B.7Convert To AlgebraWhen a problem says "all but k", it's counting the OPPOSITE — write that down, add the clues, and the total appears in one step.