Competition · AMC preparation · step 4 of 4
AMC 8 · 2013 · #22
Grade 4 countingpattern
Pick an answer.
AMC 8 2013 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Counting all 3932 toothpicks at once is hopeless, so Tool #7 (Identify Subproblems) splits the grid into two clean piles: every toothpick is either horizontal or vertical, and the two piles can be counted separately and added. To see why a grid that is n toothpicks long needs n+1 vertical lines, Tool #9 (Easier Related Problem) is perfect — shrink to a tiny 2 × 3 grid where you can count directly. Tool #1 (Draw a Diagram) just makes the "n+1 lines for n cells" fact visible (fenceposts vs. fence sections).
Try a smaller grid first
Warm up on a tiny 3-long, 2-wide grid: draw it and count by hand to get 17 toothpicks.
Building a tiny version makes the pattern 'n cells need n+1 lines' obvious — it's the fencepost rule, a Grade 4 pattern-recognition skill.
4.OA.C.5Solve An Easier Related ProblemTurn the pattern into a rule
Generalize: split into two piles — horizontal = (W+1) × L, vertical = (L+1) × W — where n cells always take n+1 lines.
Breaking the count into 'horizontal pile' and 'vertical pile' is the Tool #7 move — solve each piece, then add.
For a grid that is L cells long and W cells wide, the total number of toothpicks is (W+1) · L + (L+1) · W.
▸ Why?
Every toothpick lies either flat (horizontal) or upright (vertical) and none is both, so the total is just the horizontal count plus the vertical count.
▸ Why?
The horizontal pile and the vertical pile do not overlap and together cover every toothpick, so their two counts add back to the whole grid.
▸ Why?
The upright toothpicks form L+1 evenly spaced columns, and each column is a stack of W toothpicks, giving (L+1) · W.
▸ Why?
A straight run of L cells is walled off by L+1 vertical borders: one border on the left of each cell, plus one extra border to close the right end.
▸ Why?
Pair each cell with the border on its left — that matches the cells one-for-one with all but the last border, and the lone right-end border is the single leftover, so the borders number exactly one more than the cells.
▸ Why?
The L+1 columns are identical stacks of W toothpicks, so the count is L+1 equal groups of W, which is what multiplication measures.
▸ Why?
The flat toothpicks form W+1 evenly spaced rows, and each row is a line of L toothpicks, giving (W+1) · L — the same fencepost and equal-groups reasoning with length and width swapped.
▸ Why?
A column of W stacked cells is walled off by W+1 horizontal borders: one below each cell, plus one extra to close the top end.
▸ Why?
Pair each cell with the border just below it — the cells match one-for-one with all but the top border, and that leftover top border makes the borders number exactly one more than the cells.
▸ Why?
The W+1 rows are identical lines of L toothpicks, so the count is W+1 equal groups of L, which is multiplication.
Count the vertical toothpicks
Real grid: vertical lines number 60 + 1 = 61, each 32 tall, so vertical toothpicks = 1952.
Multiplying a 2-digit number by a 2-digit number is the Grade 4 multi-digit multiplication standard.
4.NBT.B.5Identify SubproblemsCount the horizontal toothpicks
Now horizontal: lines number 32 + 1 = 33, each 60 long, so horizontal toothpicks = 1980.
Same kind of multi-digit multiplication as the vertical count, just with the roles of length and width swapped.
4.NBT.B.5Identify SubproblemsAdd the two counts
Add the two piles: 1952 + 1980 = 3932, choice (E).
Adding the two products is the last step of the Tool #7 plan — solve each piece, then combine them.
3.OA.A.1Identify SubproblemsThis AMC 8 problem becomes simple once you split it in two — count horizontal toothpicks, count vertical toothpicks, add. The only new idea is the fencepost rule: n cells need n+1 lines, a Grade 4 pattern.
- Try a smaller grid first
- Turn the pattern into a rule
- Count the vertical toothpicks
- Count the horizontal toothpicks
- Add the two counts
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