AMC 8 · 2014 · #15
Grade 8 geometry-2d
Pick an answer.
AMC 8 2014 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The figure is busy, but the question is just x + y, so Tool #7 (Identify Subproblems) splits the work into three clean sub-questions: (a) what is the measure of one small arc, (b) what is the value of x, (c) what is the value of y. Tool #1 (Draw a Diagram) is the supporting move — adding the radii OE, OG, OA, OI to the figure turns each unknown angle on the circle into two isosceles triangles whose equal sides are radii. With those isosceles triangles in view, we can find x and y from the central angles using only the triangle-angle-sum and the straight-line (180°) fact, never needing the inscribed-angle theorem as a black box.
The 12 equal arcs fill 360°, so one small arc — the central angle at O — measures = 30°.
A full turn around the center is 360°, and we are cutting it into 12 equal slices — a Grade 4 angle-measure idea.
4.MD.C.5Identify SubproblemsDraw radii OE, OA, OG; arc E→G spans 2 small arcs, so ∠ EOG = 60°, and OA = OE = OG makes the radius triangles isosceles.
Two radii of the same circle are always equal, so any triangle made from two radii is automatically isosceles — Grade 5 "classify figures by properties."
5.G.B.4Draw A DiagramThe radius triangles are isosceles, and the angle-sum bookkeeping shows x is half of ∠ EOG: x = 30°.
Using triangle-angle sums on two isosceles triangles made of radii is an "informal argument" Grade 8 move — and the punchline is the half-the-central-angle pattern.
8.G.A.5Identify SubproblemsRepeat for y = ∠ AGI: the minor arc A→I is 4 small arcs, so ∠ AOI = 120° and y = 60°.
Re-running the same pattern on the second angle reinforces the subproblem habit and shows the half-arc rule is reusable.
8.G.A.5Identify SubproblemsAdd the parts: x + y = 30° + 60° = 90° — choice (C).
Combining the two subangle answers is the Grade 4 "angle measure is additive" closer.
4.MD.C.7Identify SubproblemsWhen an angle's vertex sits on a circle, the radii drawn to its sides make isosceles triangles — and the triangle-angle-sum trick turns the angle into half of the arc it spans.