AMC 8 · 2014 · #20
Grade 7 geometry-2d
Pick an answer.
AMC 8 2014 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The shaded region is the rectangle with three corner pieces removed, so the natural move is Tool #7 (Subproblems): compute the rectangle's area, compute each quarter-circle's area, then subtract. Tool #1 (Diagram) keeps us honest about which part of each circle sits inside the rectangle — at a corner with a 90° angle, exactly one quarter does — and lets us check on the picture that the quarter-circles do not overlap before we add them up.
The rectangle's area is DA × CD = 5 × 3 = 15 — the whole we carve corners from.
Length times width for a rectangle is the Grade 4 area formula — this is the "whole" we will carve corners out of.
4.MD.A.3Identify SubproblemsEach 90° corner traps exactly a quarter-circle, so apply the area rule π r² to each circle.
A 90° corner sweeps exactly = of the disk into the rectangle — applying the Grade 7 circle-area formula.
7.G.B.4Draw A DiagramOverlap check: 1+2=3=AB and 2+3=5=BC, so the quarter-circles only touch and add with no double-count.
Splitting the corner pieces into separate disjoint subproblems is only legal if they don't overlap — the side-length check confirms it.
7.G.B.6Identify SubproblemsAdd the three disjoint quarter-circles: 0.25π + π + 2.25π = 3.5π covered.
Disjoint pieces add — the heart of the Subproblems tool.
7.G.B.6Identify SubproblemsUncovered = 15 - 3.5π ≈ 15 - 10.99 = 4.01, closest to choice (B) 4.0.
Whole minus covered = uncovered. The numerical value 4.01 is closest to choice (B) 4.0.
7.G.B.4Identify SubproblemsThis AMC 8 problem only needs Grade 7 circle-area know-how plus the "break the shape into pieces and subtract" idea you already use for L-shaped figures.