AMC 8 · 2015 · #15
Grade 6 arithmeticlogicPick an answer.
AMC 8 2015 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The trigger words "both" and "against both" (neither) point straight at Tool #12 (Venn diagram): two overlapping circles for issues A and B, plus an outside region for the 29 students who voted no on both. Tool #7 (Identify Subproblems) splits the work into two clean steps — first find how many voted yes on at least one issue (the union), then use that union to pin down the overlap. With those two subproblems in hand the Venn diagram fills in by simple subtraction; no algebra heavier than x = a + b - u is needed.
Draw circles A and B inside a box holding all 198 voters; the 29 who voted no on both sit outside both circles.
Putting the "neither" group outside the circles separates them from anyone who voted yes on at least one issue — exactly the partition Tool #12 is built for.
4.OA.A.3Draw A Venn DiagramEveryone except those 29 is in at least one circle, so the union is 198 - 29 = 169.
Splitting the 198 voters into "in at least one circle" vs "in neither circle" is the Tool #7 subproblems move — solve the easier piece first.
4.OA.A.3Identify SubproblemsBy inclusion-exclusion, |A| + |B| counts the overlap twice, so it exceeds the union by exactly |A ∩ B|.
The Venn picture makes the double-count obvious: the lens-shaped intersection is inside both A and B, so it is counted once in |A| and again in |B|.
6.EE.B.7Draw A Venn DiagramSubstitute: |A ∩ B| = 149 + 119 - 169 = 99, choice (D).
Solving the one-variable equation x = a + b - u with given whole numbers is a straight Grade 6 substitution.
6.EE.B.7Draw A Venn DiagramOnce the Venn diagram is drawn, this AMC 8 problem only needs Grade 6 "write one equation, solve for the unknown" — the overlap pops out as 149 + 119 - 169 = 99.