AMC 8 · 2016 · #4
Grade 6 rate-ratioPick an answer.
AMC 8 2016 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question asks for a difference in minutes per mile, but the data are mixed in hours and minutes and use totals (not per-mile rates). Tool #8 (Analyze the Units) tells us to first convert each total time to minutes, then divide by miles so the unit "minutes per mile" pops out — only then can we subtract. Tool #7 (Identify Subproblems) splits the work into three clean pieces: (1) boy's pace, (2) old man's pace, (3) the difference.
Convert the boy's 3 h 30 min to 210 minutes, then divide by 15 miles to get 14 minutes per mile.
Converting hours to minutes within the same time system is exactly the Grade 5 "convert measurement units" move.
5.MD.A.1Analyze The UnitsDo the same for the old man: 4 hours is 240 minutes, divided by 10 miles gives 24 minutes per mile.
Computing a unit rate (minutes per mile) from a total time and a total distance is Grade 6 rate reasoning.
6.RP.A.3Identify SubproblemsBoth paces share the unit minutes per mile, so subtract: 24 - 14 = 10 minutes per mile more.
"How many more" with matching units is a Grade 4 multi-step word-problem subtraction.
4.OA.A.3Analyze The UnitsThis AMC 8 problem only needs the Grade 6 idea that "unit rate = total ÷ count" — divide minutes by miles, then subtract.