AMC 8 · 2019 · #8
Grade 6 arithmeticPick an answer.
AMC 8 2019 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The trap in this problem is that each percentage applies to a different total (the current bag, not the original). Tool #9 (Easier Related Problem) makes this concrete by pretending Gilda starts with exactly 100 marbles — then every percentage becomes a plain whole number we can track. Tool #7 (Identify Subproblems) splits the journey into three clean one-step "give and keep" calculations, one per friend. Tool #3 (Eliminate Possibilities) is a nice safety net at the end: among (A)20, (B)33 , (C)38, (D)45, (E)54, only one matches the value we compute, so we can confirm the choice directly.
Pretend Gilda starts with 100 marbles: the answer is a percent of her own bag, so size can't change it, and 100 makes every percent whole.
Setting the whole equal to 100 is the standard Grade 6 trick for percent problems: "percent" literally means "per 100."
6.RP.A.3Solve An Easier Related ProblemStage 1 — Pedro: he gets 20% of 100 = 20, so Gilda keeps 100 - 20 = 80 marbles (that's 80% of what she had).
Taking 20% of 100 and subtracting is one clean subproblem — exactly the Tool #7 move.
6.RP.A.3Identify SubproblemsStage 2 — Ebony: the whole is now 80, not the original 100. She gets 10% of 80 = 8, so Gilda keeps 80 - 8 = 72 marbles.
The key Grade 6 idea: each percent is applied to the current bag, so the base changes between stages.
6.RP.A.3Identify SubproblemsStage 3 — Jimmy: the whole is 72. Since 25% = , he gets × 72 = 18, so Gilda keeps 72 - 18 = 54 marbles.
Recognizing 25% = and multiplying a whole number by a unit fraction is a Grade 5 fraction-times-whole-number move.
5.NF.B.4Identify SubproblemsWe started with 100 and Gilda kept 54, so she has = 54% of the original bag — only choice (E) matches.
Once the kept amount lines up with exactly one choice, Tool #3 (Eliminate) confirms the pick with no extra work.
6.RP.A.3Eliminate PossibilitiesThis AMC 8 problem only needs Grade 6 percent reasoning — taking a percent of whatever is left at each step — that you already know!