AMC 8 · 2020 · #13
Grade 6 probabilityalgebraPick an answer.
AMC 8 2020 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
This is a multiple-choice problem with only 5 candidate values for x, so the toolkit's best AMC strategy applies: Tool #6 (Guess and Check) plugs each choice into and compares to , while Tool #3 (Eliminate Possibilities) rules out anything that isn't . As a sanity check, Tool #15 (Reorganize Information) notices that the non-purple socks (6+12=18) never change, so purple : non-purple must equal 3 : 2 — which forces purple = 27 and confirms x = 9 without any algebra.
Count the starting socks: 6 + 18 + 12 = 36, and rewrite 60% as the fraction .
Turning 60% into the ratio 3 : 5 is a Grade 6 percent-as-ratio move and sets up clean checking.
6.RP.A.3Guess And CheckAfter adding x purple socks, the target ratio is = .
Writing the new purple fraction as a single expression in x is just Grade 6 ratio writing — we have not solved any equation yet.
6.RP.A.3Guess And CheckPlug each choice into ; only x=9 lands on = , eliminating the rest.
Recognizing and as equivalent fractions (both shrink by dividing top and bottom by 9) is a Grade 4 equivalence skill.
4.NF.A.1Eliminate PossibilitiesCross-check: non-purple (6+12=18) never changes, so purple : non-purple = 3 : 2, purple = 27, x = 27-18 = 9.
Switching from purple : total to purple : non-purple uses the fact that the unchanged quantity is the safe anchor — pure Grade 6 ratio thinking.
6.RP.A.3Organize Information In More WaysThis AMC 8 problem only needs Grade 6 ratio reasoning — turning 60% into the 3 : 5 ratio you already know!