AMC 8 · 2020 · #14
Grade 6 arithmetic
Pick an answer.
AMC 8 2020 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The chart already gives us the answer to a later step in the average calculation: the average was found by taking the total and dividing by 20. So we just undo that division — Tool #11 (Work Backwards) — by multiplying the average back by 20. Tool #1 (Draw a Diagram) is used to read the dashed line's value off the y-axis carefully (the small tick marks between the labeled gridlines matter). Tool #3 (Eliminate Possibilities) is the natural AMC closer: once we compute a total, we pick the closest of the five round choices.
Read the dashed line off the scaled y-axis: it sits halfway between the 4,500 and 5,000 ticks, so the average reads as 4,750.
Reading a value off a bar-graph's scaled y-axis is exactly the Grade 3 scaled bar-graph skill.
3.MD.B.3Draw A DiagramBy definition the dashed average is the total divided by 20, so working backwards, total = average × 20.
Knowing that an average summarizes a whole data set with one number (so that number times the count gives back the sum) is the Grade 6 "measure of center" idea.
6.SP.A.3Work BackwardsSubstitute 4,750 into that relation: 4,750 × 20 = 4,750 × 2 × 10 = 95,000.
Multiplying a four-digit number by a one-digit number and then by 10 is a Grade 4 multi-digit multiplication.
4.NBT.B.5Work BackwardsThe choices are spaced 10,000 apart and 95,000 is exactly one of them, so the closest option is (D).
Comparing whole-number magnitudes to pick the nearest choice is a Grade 4 place-value comparison.
4.NBT.A.2Eliminate PossibilitiesThis AMC 8 problem only needs Grade 6 "mean as a measure of center" — once you know average × count = total, you already know enough to solve it!