AMC 10 · 2019 · #3
Grade 6 arithmeticPick an answer.
AMC 10 2019 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #7 (Subproblems): split into (a) find total non-players, (b) split them into 'senior non-players' and 'non-senior non-players' using the per-group percentages, (c) find the non-senior total, (d) take 70% to get non-senior players. Tool #8 (Units): every number is 'students' or 'percent of students' — translate carefully. Tool #6 (Guess and Check): plug in each answer choice as 'non-seniors who play', back out the non-senior total (÷ 0.7), then the senior total (500 - that), then check the total non-player count matches 234 — saves algebra entirely.
The whole school is 500 and 46.8% don't play, so non-players total 0.468 · 500 = 234.
Percent of total = fraction of 500 — compute it once and lock it in.
6.RP.A.3Identify SubproblemsLet N be non-seniors, seniors = 500 - N; the two non-playing groups sum to the total: 0.6(500 - N) + 0.3 N = 234.
Add up the two non-playing groups and match the total.
6.EE.B.7Identify SubproblemsTest (B): non-seniors = 154 ÷ 0.7 = 220; non-players = 0.6·280 + 0.3·220 = 234 — match!
Plug a candidate in, work both sides, watch for 234.
6.RP.A.3Guess And CheckEvery other choice fails — (A)(C)(D) give a non-whole N, and (E) 266 gives non-players 186 ≠ 234 — so the answer is 154.
One clean match — the rest fail the whole-number or total-non-player test.
6.RP.A.3Eliminate PossibilitiesThis AMC 10 problem only needs Grade 6 percent reasoning you already know — find 234 total non-players, then test the choices: 154 non-senior players means 220 non-seniors and 280 seniors, giving 168 + 66 = 234 non-players. Match — (B)!