AMC 10 · 2003 · #11

Grade 6 rate-ratio
rateratio-proportionunit-conversion dimensional-analysisconvert-to-algebra ↑ Prerequisites: ratio-proportion
📏 Long solution 💡 2 insights
Problem
A watch is set correctly at noon and then runs slow at a steady rate. One hour of real time later, the watch has only advanced 57 minutes and 36 seconds. Find the real clock time at the moment the watch face first shows 10:00 PM.

Pick an answer.

(A)
10:22 PM and 24 seconds
(B)
10:24 PM
(C)
10:25 PM
(D)
10:27 PM
(E)
10:30 PM
How to solve
Strategy Analyze the Units

There are two different clocks ticking, so the safe move is to keep the units straight (Tool #8): every quantity is either "watch minutes" or "real minutes", and the one hour of data converts between them. Turn that hour into a unit rate — watch minutes per real minute — and the whole problem becomes a single conversion. Measure both times from noon in minutes so nothing has to be carried across an hour boundary (Tool #4), then write the conversion as one proportion and solve it (Tool #13). Finally convert the answer back into clock form and check it against the choices, since a near-miss choice sits only one minute away (Tool #3).

1STEP 1

Turn the observed hour into minutes

In shared units the watch gains 57.6 minutes for every 60 real ones.

36 s=36/60 min=0.6 min → 57 min 36 s=57.6 min
2STEP 2

Find the watch-to-real unit rate

That fixes the rate at 24 watch minutes per 25 real ones.

watch/real=57.6/60=24/25 → real=25/24×watch
3STEP 3

Measure the target on the watch

The target is on the watch, so it is 600 watch minutes after noon.

watch elapsed=10 × 60=600 min; x=real minutes after noon
4STEP 4

Solve the proportion

Scaling the right way round gives 625 real minutes.

600/x=24/25 → 24x=15000 → x=625
5STEP 5

Convert back to a clock time

That is 10:25 PM, and a minute earlier the watch has not arrived, choice (C).

625=10 · 60+25 → 10:25 PM; 624 × 0.96=599.04 < 600
Answer
10:25 PM
The answer is self-consistent. The watch falls behind by 60-57.6=2.4 minutes for every real hour. From noon to 10:25 PM is 625 real minutes, or 625/60 hours, so the accumulated loss is 2.4×625/60=25 minutes — exactly the gap between the watch's 10:00 PM and the real 10:25 PM. The direction is right too: a slow watch must be read later in real time, and 10:25 PM is after 10:00 PM. The tempting wrong answer is (B) 10:24 PM, which charges the 2.4 minutes per hour loss to 10 hours instead of to the 10 5/12 real hours that actually elapse; that undercount of 1 minute is exactly the difference between the two choices.
💡Key takeaway

A steadily slow watch runs on its own scale — 24 watch minutes for every 25 real minutes — so multiply whatever the watch says by 25/24 to get the real time.

  • Turn the observed hour into minutes
  • Find the watch-to-real unit rate
  • Measure the target on the watch
  • Solve the proportion
  • Convert back to a clock time