AMC 10 · 2003 · #4
Grade 6 rate-ratioPick an answer.
The question is a chain of rates and measurements — inches, feet, square feet, feet-per-hour — so Tool #8 (Analyze the Units) is the spine: keeping every quantity in feet forces the arithmetic to line up and stops the classic mistake of dividing area straight by speed. Tool #7 (Identify Subproblems) splits the job into three clean pieces: the real cutting width, the lawn's area, and the total walking distance, each a single easy step. Tool #3 (Eliminate Possibilities) then guards the finish: forgetting the overlap or forgetting the swath entirely lands on one of the trap choices, so checking the units confirms the answer is the one that survives.
Find the real cutting width
The overlap means fresh grass per pass is 28 minus 4, or 2 feet once converted.
Overlap means part of each pass is wasted, so the width that counts is the swath minus the overlap.
5.MD.A.1Analyze The UnitsFind the lawn's area
The lawn's area is 90 times 150, or 13500 square feet.
All the grass has to be covered, and for a rectangle that total is just its two sides multiplied.
4.MD.A.3Identify SubproblemsTurn the area into walking distance
Seen as one long strip, the walking distance is the area over the width: 6750 feet.
A strip of known area and known width has a length you get by dividing area by width.
A strip of known area and known width has a length you get by dividing one by the other.
▸ Why?
A strip's area is its width repeated along its length, which is a count of equal groups.
▸ Why?
Dividing undoes multiplying, so the area shared by the width hands back the length.
Divide distance by speed
Dividing by the walking speed gives 1.35 hours, choice (C).
At a steady walking speed, time is simply how far you go divided by how fast you go.
6.RP.A.3Analyze The UnitsTurn the whole mowed lawn into one long strip: its area divided by its width is the distance you walk, and distance divided by speed is the time.
- Find the real cutting width
- Find the lawn's area
- Turn the area into walking distance
- Divide distance by speed