AMC 10 · 2003 · #9

Grade 8 algebra
slope-interceptfunction-evaluationrate convert-to-algebrapattern-recognition ↑ Prerequisites: slope-intercept
📏 Medium solution 💡 2 insights
Problem
f is a linear function — its graph is a straight line. Moving the input from 2 to 6 raises the output by 12. Find how much the output rises when the input moves from 2 to 12 instead.

Pick an answer.

(A)
12
(B)
18
(C)
24
(D)
30
(E)
36
How to solve
Strategy Introduce a Variable

The function is not handed over — only one fact about it is. Tool #4 (Introduce a Variable) writes the unknown line as f(x)=mx+b with both constants named, which makes the key event visible: b cancels out of every difference f(q)-f(p), so the missing information was never needed. Tool #5 (Look for a Pattern) supplies the reason behind the cancellation — on a straight line, equal runs always produce equal rises — and gives a second, formula-free route to the same number. Tool #3 (Eliminate Possibilities) is used at the end to see which wrong choices the standard slips would produce, since each distractor here matches a specific mis-scaling.

1STEP 1

Name the line

Write the line in general form; neither the slope nor the height is given.

f(x)=mx+b, m,b fixed but unknown
2STEP 2

The height b cancels in every difference

In any difference of outputs the height cancels, leaving slope times run.

f(q)-f(p)=(mq+b)-(mp+b)=m(q-p)
3STEP 3

Read the slope off the given fact

The given rise over a run of 4 gives slope 3.

f(6)-f(2)=m(6-2)=4m=12 ⟹ m=3
4STEP 4

Apply the same rule to the longer run

The asked run is 10, not 12, so the rise is 30, choice (D).

f(12)-f(2)=m(12-2)=3 · 10=30 → (D)
Answer
30
Scale check without any algebra: the second run, 10, is 10/4=2.5 times the first run, 4, so the rise must be 2.5 × 12=30. Every wrong choice matches a named slip. (A) 12 takes the rise to be unchanged by a longer run. (C) 24 doubles because 12 is twice 6, forgetting both differences start at 2. (E) 36 multiplies by 12/4=3, using the endpoint 12 as the run instead of 12-2=10. (B) 18 matches no consistent reading at all. A concrete test also confirms the result and shows the vertical position is genuinely irrelevant: for f(x)=3x+100, f(6)-f(2)=118-106=12 as required, and f(12)-f(2)=136-106=30.
💡Key takeaway

On a straight line only the run decides the rise — how high the line starts cancels out of every difference, so you never need to know the whole function.

  • Name the line
  • The height b cancels in every difference
  • Read the slope off the given fact
  • Apply the same rule to the longer run