AMC 10 · 2004 · #10

Grade 6 arithmetic
mean-median-mode-rangesequences-arithmeticexponents symmetry-argumentconvert-to-algebra ↑ Prerequisites: mean-median-mode-range
📏 Medium solution 💡 1 insight
Problem
Forty-nine integers in a row — each one more than the last — add up to 7⁵. Find the median of those 49 integers.

Pick an answer.

(A)
7
(B)
$7^2$
(C)
$7^3$
(D)
$7^4$
(E)
$7^5$
How to solve
Strategy Introduce a Variable

The natural instinct is to name the first term, but then the sum drags in 1+2+…+48. Tool #4 with a better choice of variable — name the middle term instead — makes the list symmetric about the unknown, and Tool #15 (writing the list centred on its median rather than starting from its front) makes the outer terms cancel in pairs. The sum then collapses to 49 copies of the middle term, and one division finishes the problem. Tool #3 is the last step: the choices are all powers of 7, so the numerical answer has to be matched back to a power.

1STEP 1

Locate the median in the list

With an odd count the median is a real member — here the 25th term.

49 = 24 + 1 + 24 → median = the 25th term
2STEP 2

Name the middle term

Naming it and writing the rest as offsets centres the whole list.

m-24, m-23, …, m, …, m+23, m+24
3STEP 3

Add by pairing outward from the middle

Pairing outward cancels every offset, so the sum is just 49 times the median.

sum = 24·(2m) + m = 48m + m = 49m
4STEP 4

Solve for the middle term

Dividing the given total gives 343.

49m = 7⁵ = 16807 ⟹ m = 16807/49 = 343
5STEP 5

Match 343 to a power of 7

Written as a power of seven that is , choice (C).

343 = 7 · 7 · 7 = 7³ → (C)
Answer
Multiply back: 49 · 343 = 16807, and 16807 = 7⁵, so the sum checks out. The list itself is also real and made of integers: it runs from 343-24=319 up to 343+24=367, all whole numbers, and its middle term is indeed 343. A quick scale check confirms no neighbouring choice can work — a median of 7² gives a sum of 7⁴ (too small by a factor of 49) and a median of 7⁴ gives a sum of 7⁶ (too big by the same factor).
💡Key takeaway

In a list of consecutive numbers the middle one is also the average, so the sum is just the count times the median — divide 16807 by 49 and you get 343.

  • Locate the median in the list
  • Name the middle term
  • Add by pairing outward from the middle
  • Solve for the middle term
  • Match 343 to a power of 7