AMC 10 · 2004 · #4

Grade 4 arithmetic
multi-digit-arithmetic identify-subproblemscomplementary-counting ↑ Prerequisites: mental-arithmetic
📏 Medium solution 💡 1 insight
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Problem
Bertha has 6 daughters; some of them each have exactly 6 daughters of their own and the rest have none. Counting daughters and granddaughters together gives 30 women, and no one in the next generation exists. Find how many of these 30 women have no daughters.

Pick an answer.

(A)
22
(B)
23
(C)
24
(D)
25
(E)
26
How to solve
Strategy Identify Subproblems

The count of 30 mixes two generations, so first split off the fixed 6 daughters to find the number of granddaughters, then use that to find how many daughters became mothers. Once those pieces are known, the women with no daughters are just the granddaughters plus the childless daughters, so the whole task breaks into a few small counting steps.

1STEP 1

Count the granddaughters

Removing the six daughters from the total leaves 24 granddaughters.

30 - 6 = 24 granddaughters
2STEP 2

Find how many daughters are mothers

Each mother has exactly six, so dividing gives 4 mothers.

24 ÷ 6 = 4 daughters are mothers
3STEP 3

Find the childless daughters

That leaves 2 daughters with no children of their own.

6 - 4 = 2 daughters with no daughters
4STEP 4

Add up everyone with no daughters

Every granddaughter is childless too, so the total is 26, choice (E).

24 + 2 = 26
Answer
26
Check the count both ways. Women who DO have daughters are only the 4 mother-daughters, and 30 - 4 = 26, which agrees with the direct count of 24 + 2 = 26. Also 26 is less than 30 and larger than the 24 granddaughters alone, exactly as expected.
💡Key takeaway

When a count mixes two groups, peel off the group you already know, then the pieces are easy to add back up.

  • Count the granddaughters
  • Find how many daughters are mothers
  • Find the childless daughters
  • Add up everyone with no daughters