AMC 10 · 2004 · #1

Grade 4 arithmetic
sequences-geometricmulti-digit-arithmetic work-backwardspattern-recognition ↑ Prerequisites: multi-digit-arithmetic
📏 Medium solution 💡 2 insights
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Problem
Jenny doubles her free throws every practice. At the fifth practice she made 48. Find how many she made at the first practice.

Pick an answer.

(A)
3
(B)
6
(C)
9
(D)
12
(E)
15
How to solve
Strategy Work Backwards

The problem hands you the END of the chain (the fifth practice, 48) and asks for the START (the first practice). Tool #11 (Work Backwards) fits exactly: instead of building up, undo the rule one step at a time. Forward the rule is "multiply by 2," so backward it is "divide by 2." Tool #5 (Look for a Pattern) names the structure — a doubling chain — so you know there are exactly four backward steps from the fifth practice to the first.

1STEP 1

See the doubling chain

From the first to the fifth practice the doubling is applied four times.

1st → 2nd → 3rd → 4th → 5th=48
2STEP 2

Undo one doubling

Undoing one doubling means halving: the fourth practice is 24.

48÷2=24 (4th practice)
3STEP 3

Keep halving back to the first

Halving on back gives 12, then 6, then 3.

24÷2=12, 12÷2=6, 6÷2=3
4STEP 4

Read off and check the answer

Walking forward lands exactly on 48, so the answer is 3, choice (A).

3 → 6 → 12 → 24 → 48 → (A)
Answer
3
Doubling grows fast, so after four doublings the first-practice number must be much smaller than 48 — and 3 is. All the answer choices are small, which is the tell that the first practice is a tiny seed that blows up to 48. Forward-checking 3→6→12→24→48 hits 48 on the nose at the fifth practice, so nothing was over- or under-halved. A choice like 6 (B) would land on 96 by the fifth practice, far too big, so it is ruled out.
💡Key takeaway

When the end of a doubling chain is given and you want the start, walk backward by halving one step at a time.

  • See the doubling chain
  • Undo one doubling
  • Keep halving back to the first
  • Read off and check the answer