AMC 10 · 2004 · #11

Grade 7 algebra
mean-median-mode-rangeextreme-principlelinear-equations-one-var extremal-constructionconvert-to-algebra ↑ Prerequisites: mean-median-mode-range
📏 Medium solution 💡 3 insights
Problem
On a test worth 100 points, exactly five students scored 100 and nobody scored below 60. The class average was 76. Find the smallest class size that is actually possible.

Pick an answer.

(A)
10
(B)
11
(C)
12
(D)
13
(E)
14
How to solve
Strategy Extreme Principle

The five 100s drag the average up, and the only thing that can drag it back down to 76 is a supply of low scores. Tool #4 (Introduce a Variable) names the class size n and turns the mean into a fixed total. Tool #14 (Extreme Principle) asks how far down the other students can possibly pull the total: they are floored at 60, so there is a hard limit, and that limit becomes an inequality in n. Tool #13 (Convert to Algebra) solves it. The inequality only rules small classes out, so Tool #6 (Guess and Check) finishes by exhibiting one honest score list for the surviving size.

1STEP 1

Turn the mean into a total

The average becomes a total, which is far easier to control.

mean=total/n=76 ⟺ total=76n
2STEP 2

Push everyone else to the floor

Pushing everyone else to the floor gives the smallest possible total.

total ≥ 500+60(n-5)=60n+200
3STEP 3

Compare the floor with the required total

The floor must not exceed what is required, forcing at least 13.

60n+200 ≤ 76n → 200 ≤ 16n → n ≥ 25/2=12.5 → n ≥ 13
4STEP 4

Build a class of 13 that works

A class of 13 really exists with eight scores of 61, so the answer is 13, choice (D).

13 · 76=988, 988-500=488, 488/8=61, 60 ≤ 61 < 100 (D)
Answer
13
Check the rejected size directly instead of trusting the algebra. With n=12 the total would have to be 12 × 76=912, but the smallest total 12 students could have is 500+7 × 60=920, and 920 > 912: even if all seven non-perfect scorers bottom out at 60, the class average stays above 76. So 12 is genuinely impossible and 13 is genuinely possible, which is exactly what 'smallest' demands. The size 12.5 that pops out of the inequality is not an answer on its own; it is a threshold, and the whole-number answer is the next integer above it.
💡Key takeaway

Five perfect scores push the average up, and only students sitting at the 60-point floor can pull it back down, so count how many floor-sitters you need and then actually build the class to prove that size works.

  • Turn the mean into a total
  • Push everyone else to the floor
  • Compare the floor with the required total
  • Build a class of 13 that works