AMC 10 · 2007 · #1

Grade 4 geometry-2d
area-rectanglessurface-areamulti-digit-arithmetic identify-subproblems ↑ Prerequisites: area-rectangles
📏 Short solution 💡 1 insight
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Problem
Three identical bedrooms have only their four walls painted. In each room a fixed area of doorways and windows is left unpainted. Find the total painted wall area.

Pick an answer.

(A)
678
(B)
768
(C)
786
(D)
867
(E)
876
How to solve
Strategy Identify Subproblems

The total is built from several smaller pieces — the area of one bedroom's four walls, the unpainted doorways/windows, and the fact that there are three bedrooms — so Tool #7 (Identify Subproblems) solves it one layer at a time: one wall, one bedroom, then all three. Tool #1 (Draw a Diagram) keeps the box straight so that only the four vertical walls (two 12×8 and two 10×8) are counted and the floor and ceiling are correctly left out.

1STEP 1

Find the area of the four walls

The four walls come in two matching pairs.

12×8=96, 10×8=80
2STEP 2

Add up one bedroom's walls

One room's walls total 352.

2×96+2×80=192+160=352
3STEP 3

Subtract the doorways and windows

Subtracting the openings per room leaves 292.

352-60=292
4STEP 4

Multiply by the three bedrooms

Multiplying by the three rooms gives 876, choice (E).

292×3=876 → (E)
Answer
876
A quick sanity check: one bedroom's walls total 352 sq ft, and 60 sq ft of that is not painted, leaving roughly 290 sq ft per room. Three rooms is about 3×290≈870 sq ft, right next to 876. The answer must also be a multiple of 3 (three identical rooms), and 876=3×292 passes, while none of the trap choices are as clean. The height 8 appears in every wall, so 876 being a bit under 900 fits three medium rooms.
💡Key takeaway

Break a room into its four rectangular walls, add them up, take out the openings, then multiply by the number of identical rooms.

  • Find the area of the four walls
  • Add up one bedroom's walls
  • Subtract the doorways and windows
  • Multiply by the three bedrooms