AMC 10 · 2008 · #4

Grade 5 algebra
fraction-multiplicationpattern-recognitiontelescoping-sum pattern-recognitioneasier-related-problem ↑ Prerequisites: fraction-multiplication
📏 Medium solution 💡 2 insights
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Problem
A long chain of fractions is multiplied together, each one's bottom matching the previous top. Find the product.

Pick an answer.

(A)
251
(B)
502
(C)
1004
(D)
2008
(E)
4016
How to solve
Strategy Look for a Pattern

Multiplying 501 fractions head-on is hopeless, so Tool #9 (Solve an Easier Related Problem) says try just the first two or three factors first. That reveals a repeating cancellation, and Tool #5 (Look for a Pattern) explains it: the top of each fraction is the bottom of the next one. Tool #7 (Identify Subproblems) then lets me write the whole thing as one big fraction, cancel every matching pair, and finish with a single easy division.

1STEP 1

Multiply the first few factors

Multiplying the first few factors shows a pattern.

8/4·12/8=12/4=3, 12/4·16/12=16/4=4
2STEP 2

See why a number always cancels

The tops and bottoms are the same list, shifted by one.

tops: 8,12,16,…,2008; bottoms: 4,8,12,…,2004
3STEP 3

Cancel everything in the middle

So everything cancels but the two ends.

(8·12·16…2008)/(4·8·12…2004)=2008/4
4STEP 4

Do the final division

Dividing gives 502, choice (B).

2008/4=502 → (B)
Answer
502
Check the division: 502·4=2008, so 2008/4=502 is right. The size is sensible too — each factor is only a little bigger than 1 (about 2, 1.5, 1.33, …), so multiplying about 500 of them lands well below the largest choices. The traps line up with common slips: 2008 (D) forgets to divide by the first denominator, 4016 (E) doubles instead, and 251 (A) is 2008/8 from cancelling one number too many.
💡Key takeaway

When the top of each fraction is the bottom of the next, they cancel down the line, so only the very last top and the very first bottom are left.

  • Multiply the first few factors
  • See why a number always cancels
  • Cancel everything in the middle
  • Do the final division