AMC 10 · 2008 · #2

Grade 2 arithmetic
symmetry-argumentmulti-digit-arithmetic identify-subproblems ↑ Prerequisites: mental-arithmetic
📏 Medium solution 💡 2 insights
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Problem
A four by four block of numbers has two of its rows reversed left to right. Find the difference between the two diagonal sums.

Pick an answer.

(A)
2
(B)
4
(C)
6
(D)
8
(E)
10
How to solve
Strategy Draw a Diagram

The whole difficulty is keeping track of which number sits in which cell after two rows flip, so Tool #1 (Draw a Diagram) — literally rewriting the block with rows 2 and 4 reversed — removes every chance of grabbing the wrong number off a diagonal. Once the new block is drawn, Tool #7 (Identify Subproblems) splits the job into three tiny, independent calculations: sum one diagonal, sum the other, subtract.

1STEP 1

Redraw the block after reversing

Redrawing the block makes both diagonals readable.

1&2&3&4 ; 11&10&9&8 ; 15&16&17&18 ; 25&24&23&22
2STEP 2

Add the main diagonal

One diagonal adds to 50.

1+10+17+22=50
3STEP 3

Add the other diagonal

The other adds to 54.

4+9+16+25=54
4STEP 4

Take the positive difference

The positive difference is 4, choice (B).

54-50=4 → (B)
Answer
4
Before any reversal, both diagonals of this calendar block already sum to the same value 52 (main 1+9+17+25=52, anti 4+10+16+22=52), so a difference can only come from the cells the flip actually moves. On the main diagonal the moved cells change 9→10 (+1) and 25→22 (-3), a net -2, giving 50. On the other diagonal they change 10→9 (-1) and 22→25 (+3), a net +2, giving 54. A shift of -2 against +2 makes a gap of exactly 4, matching (B), and the answer is a small even number as all the choices are.
💡Key takeaway

When numbers move around a grid, redraw the grid first and then read the diagonals off the new picture instead of your memory.

  • Redraw the block after reversing
  • Add the main diagonal
  • Add the other diagonal
  • Take the positive difference