AMC 10 · 2009 · #12

Grade 8 algebra
sequences-geometricexponentsfactoriallinear-equations-one-var convert-to-algebraidentify-subproblems ↑ Prerequisites: sequences-geometricfactorial
📏 Medium solution 💡 2 insights
Problem
A geometric sequence has two of its terms given as factorials three positions apart. Find its first term.

Pick an answer.

(A)
60
(B)
75
(C)
120
(D)
225
(E)
315
How to solve
Strategy Introduce a Variable

Tool #4 (Introduce a Variable) names the two things that describe the whole sequence: the first term a and the ratio r. Then the work splits into two independent subproblems (tool #7): find r, then find a. The ratio falls out because the fifth and eighth terms are three steps apart, so dividing them cancels a entirely, and the right-hand side is 8!/7! = 8 straight from the definition of factorial. Tool #3 (Eliminate Possibilities) does the part the quick solution skips — showing r = 2 is the only real cube root of 8, which is exactly where the words "of real numbers" earn their place. Tool #6 (Guess and Check) finishes by building the sequence and confirming it really has the two required terms.

1STEP 1

Name the first term and the ratio

Naming the first term and ratio writes both given terms.

ar⁴ = 7! = 5040, ar⁷ = 8! = 40320
2STEP 2

Divide to cancel the first term

Dividing cancels the first term and the factorials.

ar⁷/ar⁴ = r³ = 8!/7! = (8 · 7!)/7! = 8
3STEP 3

Why r has to be exactly 2

Factoring shows the ratio is exactly two.

r³ - 8 = (r-2)((r+1)² + 3), (r+1)² + 3 ≥ 3 > 0 → r = 2
4STEP 4

Back out the first term

Backing out gives the first term as 315.

a · 2⁴ = 16a = 5040 → a = 5040/16 = 315
5STEP 5

Check the sequence actually exists

Writing the sequence out confirms it, choice (E).

315, 630, 1260, 2520, 5040 = 7!, 10080, 20160, 40320 = 8! → (E)
Answer
315
Every choice can be tested directly against the rule "double four times to reach the fifth term": 60 → 960, 75 → 1200, 120 → 1920, 225 → 3600, 315 → 5040. Only 315 lands on 7! = 5040, so the other four are ruled out by a concrete failure rather than by trusting the algebra. The size is sensible too: the first term should be about 1/16 of the fifth term because of the four doublings, and 5040/16 = 315 matches. The sequence also increases, which it must, since 8! > 7! forces a ratio bigger than 1.
💡Key takeaway

Dividing a later term of a geometric sequence by an earlier one wipes out the starting value, so the gap between two known terms tells you exactly what you are multiplying by.

  • Name the first term and the ratio
  • Divide to cancel the first term
  • Why r has to be exactly 2
  • Back out the first term
  • Check the sequence actually exists