AMC 10 · 2010 · #21

Grade 11 algebra
polynomial-rootspolynomial-factoringsign-analysis convert-to-algebraidentify-subproblems ↑ Prerequisites: polynomial-roots
📏 Long solution 💡 3 insights
Problem
A sixth-degree curve sits above a line everywhere and touches it at exactly three places. Find the largest touching point.

Pick an answer.

(A)
4
(B)
5
(C)
6
(D)
7
(E)
8
How to solve
Strategy Introduce a Variable

Tool #16 (Change Focus): comparing two graphs is awkward, so I stop looking at the curve and the line separately and look only at their difference D(x); the whole hypothesis becomes one sentence about a single polynomial. Tool #14 (Extreme Principle): every meeting point is a place where D hits its floor value 0 without ever going lower, and that boundary behaviour is what forces each root to be a double root — three doubles then use up all six degrees exactly, so D must be the square of a cubic. Tool #4 (Introduce a Variable): I name that cubic x³-ux²+vx-w with unknown u,v,w, square it once in general letters, and match coefficients; the unknowns a,b,c only touch the bottom three coefficients, so the top four determine u,v,w on their own. Tool #3 (Eliminate Possibilities): at the end I test the answer choices directly in the cubic, which both checks the factoring and kills the other four choices.

1STEP 1

Compare by subtracting

Subtracting turns the comparison into one sign question.

D(x)=x⁶-10x⁵+29x⁴-4x³+ax²-bx-c ≥ 0, with equality at exactly 3 values of x
2STEP 2

A touching zero is a double zero

Every touching root must be double.

D(x)=(x-r)^m h(x), h(r) ≠ 0, D ≥ 0 → m is even
3STEP 3

Three double zeros fill degree 6

Three double roots fill the degree exactly.

D(x)=(x-p)²(x-q)²(x-r)²=[(x-p)(x-q)(x-r)]²
4STEP 4

Square a cubic in general letters

So the difference is a cubic squared.

(x³-ux²+vx-w)²=x⁶-2ux⁵+(u²+2v)x⁴-(2uv+2w)x³+(v²+2uw)x²-2vwx+w²
5STEP 5

Match the four known coefficients

The four known coefficients fix that cubic.

-2u=-10, u²+2v=29, 2uv+2w=4 → u=5, v=2, w=-8
6STEP 6

Factor the cubic

It factors into three whole-number roots.

x³-5x²+2x+8=(x+1)(x-2)(x-4) → p,q,r=-1, 2, 4
7STEP 7

Confirm the picture is real, then read off the answer

The largest of them is 4, choice (A).

a=-76, b=-32, c=-64; D(x)=[(x+1)(x-2)(x-4)]²; max{-1,2,4}=4 (A)
Answer
4
The three roots pass every Vieta check against the given coefficients: -1+2+4=5, which is half of the 10 in the x⁵ term; (-1)(2)+(2)(4)+(4)(-1)=2, matching u²+2v=25+4=29; and (-1)(2)(4)=-8, matching 2uv+2w=20-16=4. A direct value check also works: with a=-76, b=-32, c=-64, the difference D takes the values 576, 0, 64, 36, 0, 16, 0, 324 at x=-2,-1,0,1,2,3,4,5 — never negative, and zero only at -1, 2, 4. The other choices fail hard, since none of 5, 6, 7, 8 is a root of x³-5x²+2x+8. Note also that the answer never needed a, b, or c, which is the sign the problem was designed around the four visible coefficients.
💡Key takeaway

A polynomial that is never negative can only touch zero, never cross it, so every touch is a double root - and three touches use up a degree-6 polynomial exactly, forcing it to be the square of a cubic.

  • Compare by subtracting
  • A touching zero is a double zero
  • Three double zeros fill degree 6
  • Square a cubic in general letters
  • Match the four known coefficients
  • Factor the cubic
  • Confirm the picture is real, then read off the answer