AMC 10 · 2012 · #1

Grade 4 arithmetic
multi-digit-arithmeticmental-arithmetic identify-subproblems ↑ Prerequisites: mental-arithmetic
📏 Short solution 💡 1 insight
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Problem
Every classroom holds the same numbers of students and rabbits. Find the excess of students over rabbits.

Pick an answer.

(A)
48
(B)
56
(C)
64
(D)
72
(E)
80
How to solve
Strategy Identify Subproblems

The question bundles two counts (students and rabbits) over 4 rooms, so Tool #7 (Identify Subproblems) splits it into clean pieces: total students, total rabbits, then their difference. Tool #3 (Eliminate Possibilities) catches the classic trap of stopping at 72 (the student total, choice (D)) instead of subtracting the rabbits.

1STEP 1

Count all the students

All the students come to 72.

18 × 4 = 72
2STEP 2

Count all the rabbits

All the rabbits come to 8.

2 × 4 = 8
3STEP 3

Subtract to find how many more

Subtracting gives 64, choice (C).

72 - 8 = 64 → (C)
Answer
64
Sanity check with the per-room shortcut: each room has 18 - 2 = 16 more students than rabbits, and 16 × 4 = 64 — the same answer, which confirms 64. The value also sits sensibly below the student total of 72, since removing 8 rabbits should trim only a little. Choice (D) 72 is exactly the un-subtracted student count, the trap the question is testing.
💡Key takeaway

Scale each count up to all the rooms first, then subtract — "how many more" always means take the smaller total away from the bigger one.

  • Count all the students
  • Count all the rabbits
  • Subtract to find how many more