AMC 10 · 2013 · #14

Grade 11 algebrapattern
logarithm-propertiessequences-arithmeticsequences-geometricprime-factorization identify-subproblemsconvert-to-algebra ↑ Prerequisites: logarithm-properties
📏 Medium solution 💡 2 insights
Problem
Five logarithms step evenly and the two ends are known. Find the second term's number.

Pick an answer.

(A)
$125\sqrt{3}$
(B)
270
(C)
$162\sqrt{5}$
(D)
434
(E)
$225\sqrt{6}$
How to solve
Strategy Organize Information in More Ways

The information arrives in the wrong shape: the condition is about logarithms, but the question asks about the number inside one. Tool #15 (Organize Information in More Ways) is primary — rewrite the arithmetic ladder of logarithms as a multiplicative ladder of the numbers themselves, then rewrite 162 and 1250 in prime-factored form, and the answer becomes visible with no decimals. Tool #4 (Introduce a Variable) names the step factor so the two known end numbers can be tied together in one equation. Tool #3 (Eliminate Possibilities) handles the one place this problem can bite: a fourth power hides a sign, so two real step factors solve the equation and one of them must be thrown out. Tool #7 (Identify Subproblems) splits the work honestly into two halves — first show what x is forced to be, then show a progression with that x actually exists.

1STEP 1

Turn the log ladder into a number ladder

The ladder becomes a multiplying one.

r=12^d > 0, 162, 162r, 162r², 162r³, 162r⁴=1250
2STEP 2

Tie the two ends together

The two ends fix the ratio.

162r⁴=1250 → r⁴=1250/162=625/81
3STEP 3

Read the fourth root off the primes

The primes make the fourth root obvious.

1250/162=(2 · 5⁴)/(2 · 3⁴)=5⁴/3⁴=(5/3)⁴
4STEP 4

Kill the second fourth root

A positive base kills the negative root.

t⁴=(5/3)⁴→ t=±5/3; r=12^d > 0→ r=5/3
5STEP 5

Build the ladder and check it lands

Building the ladder gives 270, choice (B).

162, 270, 450, 750, 1250; d=log₁₂{5/3}; x=270 → (B)
Answer
270
Size check first: the step factor is 5/3≈ 1.67, so x should be a bit under twice 162, and 270 is. Now test the rivals by asking what fifth number each would produce. If x=125√(3)≈ 216.5 the ratio is about 1.34 and the fifth number is about 162 · 1.34⁴≈ 517; 162√(5)≈ 362 gives about 4000; 434 gives about 8300; 225√(6)≈ 551 gives roughly 21000. Only 270 closes on 1250, and it does so exactly. Decimal cross-check: log₁₂{162}≈ 2.047 and log₁₂{1250}≈ 2.870, so d≈ 0.206 and 12².047+0.206≈ 270. One more structural check: the base 12 never actually entered any calculation. That is expected — the argument only used that logarithms turn multiplying into adding, which holds in any base, so the same x would come out of base 2 or base 10. The three irrational choices are bait for anyone who takes the fourth root on a calculator and never notices it is exactly 5/3.
💡Key takeaway

When logarithms climb by equal steps, the numbers inside them grow by equal factors — so factor the two ends, 162 = 2 · 3⁴ and 1250 = 2 · 5⁴, and the step factor 5/3 falls straight out.

  • Turn the log ladder into a number ladder
  • Tie the two ends together
  • Read the fourth root off the primes
  • Kill the second fourth root
  • Build the ladder and check it lands