AMC 10 · 2013 · #4

Grade 6 rate-ratio
rateweighted-average dimensional-analysiseasier-related-problem ↑ Prerequisites: rate
📏 Short solution 💡 1 insight
Problem
Two vehicles cover the same distance at different efficiencies. Find the combined efficiency.

Pick an answer.

(A)
10
(B)
16
(C)
25
(D)
30
(E)
40
How to solve
Strategy Analyze the Units

The whole problem lives in the units "miles per gallon." Tool #8 (Analyze the Units) fixes the meaning: a combined rate is total miles divided by total gallons, so the job is to add up the miles and add up the gallons. To keep the gallons whole and avoid fractions, Tool #9 (Solve an Easier Related Problem) picks one convenient distance that both 40 and 10 divide evenly, works the numbers there, and trusts that equal distances give the same rate no matter which distance is chosen.

1STEP 1

Set up the combined rate

The combined rate is totals over totals.

combined rate = (total miles)/(total gallons)
2STEP 2

Pick one convenient distance

One convenient distance makes both amounts whole.

Ray: 40 ÷ 40 = 1 gal, Tom: 40 ÷ 10 = 4 gal
3STEP 3

Add the totals and divide

Dividing gives 16, choice (B).

(40 + 40)/(1 + 4) = 80/5 = 16 → (B)
Answer
16
The combined rate must land between the two given rates, 10 and 40, so choices (A) 10 and (E) 40 are out. Because the thirsty 10-mpg car burns most of the gas, the combined rate should sit much closer to 10 than to 40; 16 fits that, while the plain average 25 (choice C) sits right in the middle and wrongly ignores the uneven gas use.
💡Key takeaway

To combine two rates, add up the total miles and the total gallons and then divide — never just average the two rates, because the gas-guzzler counts for more.

  • Set up the combined rate
  • Pick one convenient distance
  • Add the totals and divide