AMC 10 · 2014 · #5

Grade 6 arithmetic
mean-median-mode-rangepercentageweighted-average complementary-countingconvert-to-algebra ↑ Prerequisites: percentagemean-median-mode-range
📏 Medium solution 💡 2 insights
Problem
Scores are given as percentages of the class and one group is unstated. Find the gap between mean and median.

Pick an answer.

(A)
1
(B)
2
(C)
3
(D)
4
(E)
5
How to solve
Strategy Organize Information in More Ways

The scores come as a distribution (percent of students at each score), not a plain list. Tool #15 says: lay the data out in an organized table — score, share of students, and running total — because that single table hands you both answers. The mean is the weighted sum straight from the shares; the median is wherever the running total first passes the halfway mark. First, Tool #16 fills the gap: the four groups must total 100%, so the unstated group is the complement of the others. Then Tool #4 makes the counting concrete — instead of juggling percentages, pick one convenient class size so every group becomes a whole number of students and the median is easy to point at.

1STEP 1

Find the missing group

The missing group is 25 percent.

100% - 10% - 35% - 30% = 25% scored 100 points
2STEP 2

Pick a convenient class size

A convenient class size makes every count whole.

0.10 · 20 = 2, 0.35 · 20 = 7, 0.30 · 20 = 6, 0.25 · 20 = 5 (total 2+7+6+5 = 20)
3STEP 3

Compute the mean

The mean comes to 87.

(2 · 70 + 7 · 80 + 6 · 90 + 5 · 100)/20 = (140 + 560 + 540 + 500)/20 = 1740/20 = 87
4STEP 4

Find the median

Running totals put the median at 90.

cumulative: 2 (70), 2+7=9 (80), 9+6=15 (90) → 10th and 11th = 90, median = 90
5STEP 5

Take the difference

The gap is 3, choice (C).

| 87 - 90 | = 3 → (C)
Answer
3
The result must not depend on the class size, and it doesn't: using percentages directly gives the same mean 0.10·70 + 0.35·80 + 0.30·90 + 0.25·100 = 7 + 28 + 27 + 25 = 87, and the median is still 90 because 45% of students scored below 90 while only 25% scored above it, so the halfway student sits in the 90 group. Mean 87, median 90, difference 3. The mean landing below the median also makes sense — the small but heavy tail of low 70s pulls the average down. The answer 3 is choice (C).
💡Key takeaway

A pile of percentages is really an ordered data list — build the table once and the mean pops out as a weighted average while the median is just the score sitting at the halfway mark.

  • Find the missing group
  • Pick a convenient class size
  • Compute the mean
  • Find the median
  • Take the difference