AMC 10 · 2015 · #3

Grade 6 arithmetic
mean-median-mode-range convert-to-algebra ↑ Prerequisites: mean-median-mode-range
📏 Short solution 💡 1 insight
Problem
Adding one more score lifts the average by a known amount. Find that score.

Pick an answer.

(A)
81
(B)
85
(C)
91
(D)
94
(E)
95
How to solve
Strategy Identify Subproblems

An average hides the total, so Tool #7 (Identify Subproblems) splits the work into clean pieces: first turn each average back into a sum of points, once for the 14 tests and once for all 15. Tool #11 (Work Backwards) then recovers the single missing number — Payton's score is whatever was added to the old total to make the new total, so subtract the two sums.

1STEP 1

Total of the 14 graded tests

The first average hides a total of 1120.

14 × 80 = 1120
2STEP 2

Total of all 15 tests

The second hides a total of 1215.

15 × 81 = 1215
3STEP 3

Subtract to find Payton's score

The gap is 95, choice (E).

1215 - 1120 = 95 → (E)
Answer
95
The average rose from 80 to 81 when Payton's test joined, so his score must be above 80 — which rules out (A) 81 being too low to do much and points to a clearly above-average score. A quick sanity check: to lift 14 students from an 80 average to 81 takes 14 extra points, and Payton himself must also sit at the new 81 average, so 81 + 14 = 95. Both methods give 95, choice (E).
💡Key takeaway

Turn each average back into a total by multiplying by the count, then the score you added is just the jump in the total.

  • Total of the 14 graded tests
  • Total of all 15 tests
  • Subtract to find Payton's score