AMC 10 · 2016 · #3

Grade 7 number-theory
floor-functionfraction-arithmetic formula-substitution ↑ Prerequisites: fraction-arithmetic
📏 Medium solution 💡 3 insights
Problem
A remainder rule uses a rounding-down function on a negative quotient. Evaluate it.

Pick an answer.

(A)
$-\frac{3}{8}$
(B)
$-\frac{1}{40}$
(C)
0
(D)
$\frac{3}{8}$
(E)
$\frac{31}{40}$
How to solve
Strategy Identify Subproblems

The formula looks heavy, but it is really three small jobs done in order, which is exactly what Tool #7 (Identify Subproblems) is for: first divide x by y, then take the floor of that quotient, then substitute back and subtract. Tool #4 (Introduce a Variable) keeps x=3/8 and y=-2/5 straight so each piece drops into the right slot. Tool #3 (Eliminate Possibilities) gives a fast sanity check: the result must be negative with denominator 40, which already points at one choice.

1STEP 1

Plug the numbers into the formula

The formula is applied literally.

rem(3/8,-2/5)=3/8-(-2/5)⌊ 3/8/-2/5⌋
2STEP 2

Divide the two fractions

The quotient comes out negative.

3/8/-2/5=3/8·(-5/2)=-15/16
3STEP 3

Take the floor of a negative number

Rounding it down gives -1, not zero.

⌊ -15/16⌋=⌊ -0.9375⌋=-1
4STEP 4

Substitute back and subtract

Substituting back gives -1/40, choice (B).

3/8-(-2/5)(-1)=15/40-16/40=-1/40=(B)
Answer
-1/40
The result -1/40 passes two quick tests. Sign: 3/8=15/40 is just barely smaller than 2/5=16/40, so the difference is negative, as expected. Denominator: combining eighths and fifths forces denominator 40. Only choice (B) is both negative and over 40, matching exactly.
💡Key takeaway

Floor always rounds down toward smaller numbers, so a value just below zero like -0.9375 drops to -1, not 0.

  • Plug the numbers into the formula
  • Divide the two fractions
  • Take the floor of a negative number
  • Substitute back and subtract