AMC 10 · 2016 · #1
Grade 8 algebraPick an answer.
This is one compound calculation stacked on top of another, so Tool #7 (Identify Subproblems) is the natural fit: first figure out what a⁻¹ is, then build the numerator, then divide by a. Each piece is a small, safe step. Tool #4 (Introduce a Variable) keeps the meaning of a⁻¹ front and center — a negative exponent is just 1/a — so the symbol does not become a trap.
Compute the reciprocal first
The reciprocal comes out to 2.
A negative-one exponent just flips the number over, and flipping 1/2 gives 2.
A negative-one exponent just flips the number over.
▸ Why?
A number multiplied by its reciprocal gives one, so the reciprocal is what undoes it.
▸ Why?
Turning a fraction over swaps its top and bottom without touching what the fraction counts.
Simplify the top
The top then simplifies to 5.
Once a⁻¹ is a plain number, the numerator is ordinary arithmetic you can do left to right.
6.EE.A.2Identify SubproblemsDivide by the small fraction
Dividing by the small fraction gives 10, choice (D).
Dividing by 1/2 asks "how many halves fit in 5?" — and that is 10.
6.NS.A.1Identify SubproblemsTurn the negative exponent into a reciprocal first, then it is just plug-in-and-compute that you already know.