AMC 10 · 2020 · #3

Grade 6 rate-ratio
rateunit-conversiondimensional-analysismulti-digit-arithmetic dimensional-analysisidentify-subproblems ↑ Prerequisites: rate
📏 Medium solution 💡 2 insights
Problem
A driver goes 60 miles per hour for 2 hours in a car that gets 30 miles per gallon. She is paid 0.50 dollars per mile, and her only cost is gasoline at 2.00 dollars per gallon. Find her net pay rate in dollars per hour.

Pick an answer.

(A)
20
(B)
22
(C)
24
(D)
25
(E)
26
How to solve
Strategy Analyze the Units

Tool #8 (Analyze the Units) is perfect — the question is built entirely from rates (mile/hour, mile/gallon, /mile, /gallon, /hour). Track units through and the formula writes itself. Tool #7 (Subproblems) splits the work into earnings rate, gas-cost rate, and net rate — all per hour, so we don't even need the total 120 miles. Tool #3 (Eliminate) checks the magnitude: gross is 30/hr(since60mi/hr×30/hr (since 60 mi/hr ×0.50/mi = $30/hr), so the net must be a bit less than 30 — answers ≤ 20 are out.

1STEP 1

Earnings per hour

Distance times the rate gives the hourly earnings.

60 mi/hr × 0.50/mi=0.50/mi =30 per hour
2STEP 2

Fuel cost per hour

Dividing by the mileage gives the hourly fuel cost.

60 mi/hr × (1 gal)/(30 mi) × 2.00/gal=2.00/gal =4 per hour
3STEP 3

Subtract for the net

Subtracting shows the two hours never mattered.

30/hr30/hr -4/hr = $26/hr → (E)
4STEP 4

Match the choice

The result is 26 dollars an hour.

gross = 30/hr,gas=30/hr, gas =4/hr → (E)
Answer
26
Whole-trip check (units in dollars). Distance = 60 × 2 = 120 mi. Earnings = 120 × 0.50 = 60.Gasused=120/30=4gal,costing4×2=60. Gas used = 120/30 = 4 gal, costing 4 × 2 =8. Net = 60 - 8 = 52over2hours=52 over 2 hours =26/hr. Matches (E).
💡Key takeaway

This AMC 12 problem only needs Grade 6 "ratios and rates" you already know — earnings 30/hr,gas30/hr, gas4/hr, net $26/hr.